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dezoksy [38]
2 years ago
11

A train is traveling at a constant speed and has traveled 67.5 miles in the last 11 hours.

Mathematics
1 answer:
Rudiy272 years ago
3 0

Answer:

A. d= 45t

Step-by-step explanation:

(assuming that you meant 67.5 in the last 1.5 hours)

67.5 miles = distance

1.5 hours = time

therefore:

\frac{d}{t\\} = 67.5/1.5

making your answer 45

leaving a as your correct answer:

d= 45t

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The average length of a king cobra is 3.7 m. The record length is 1.88 m longer than the average. How long is the record holder?
Ugo [173]

Answer:

The record holder is 5.58 m.

Step-by-step explanation:

3.7+1.88=5.58


3 0
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Dalia flies an ultralight plane with a tailwind to a nearby town in 1/3 of an hour. On the return trip, she travels the same dis
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Dalia had an average airspeed of ⇒ 42 miles per hour.
The average wind speed was  ⇒ 12 miles per hour.

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Sanjeet paid $32.85 for a file and 3 identical pens.Leon paid $83.50 for 2 such files and 8 such pens.Find the cost of 1 pen.
olga2289 [7]
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2 files + 8 pens = $83.50   ----------------(2)

(1) x 2 :
2 files + 6 pens = $65.70   ----------------(1a)

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5 0
2 years ago
How do you explain to estimate 368+231 in two different ways
Ludmilka [50]
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7 0
2 years ago
Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac
melomori [17]
Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ b+c=20
Equation [2] ⇒ 1.50b+5c=54.50

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; b and c, that we need to solve, then this becomes a simultaneous equation problem. 

First, rearrange Equation [1] to make either b or c the subject:
b+c=20
b=20-c

Then we substitute b=20-c into Equation [2]
1.50b+5c=54.50
1.50(20-c)+5c=54.50
30-1.50c+5c=54.50
5c-1.5c=54.50-30
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c=7

Now we know the value of c which is c=7, substitute this value into b=20-c we have b=20-7=13

Answer:
Numbers of books = 13
Numbers of CDs = 7
5 0
2 years ago
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