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netineya [11]
2 years ago
6

A triangle on a coordinate plane is translated according to the rule T-8,4(x, y). Which is another way to write this rule?

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
8 0

Answer:

C

Step-by-step explanation:

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During an experiment, Juan rolled a six-sided number cube 18 times. The number two occurred four times. Juan claimed the experim
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1) Juans claim is incorrect. The correct experimental probablilty is 2/9

Step-by-step explanation:

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A skating rink charges $0.75 to rent skates and $1.25 per hour to skate. How many hours did Penny skate if she was charged $4.50
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She was skating for 3 hours.
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Four students wrote sequences during math class. Andre mc011-1.jpg Brenda mc011-2.jpg Camille mc011-3.jpg Doug mc011-4.jpg Which
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<span>A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.

</span>The common ration is obtained by dividing the a term by the preceding term.

Given that f<span>our students wrote sequences during math class with
Andre writing -\frac{3}{4} ,\frac{3}{8} ,-\frac{3}{16} ,-\frac{3}{32} , . . .
Brenda writing </span>\frac{3}{4} ,-\frac{3}{8} ,\frac{3}{16} ,\frac{3}{32} , . . .
Camille writing \frac{3}{4} ,\frac{3}{8} ,-\frac{3}{16} ,-\frac{3}{32} , . . .
Doug writing \frac{3}{4} ,-\frac{3}{8} ,\frac{3}{16} ,-\frac{3}{32} , . . .

Notice that the common ratio for the four students is - \frac{1}{2}.

For Andre, the last term is wrong and hence his sequence is not a geometric sequence.
For Brenda, the last term is wrong and hence her sequence is not a geometric sequence.
For Camille, her sequence is not a geometric sequence.
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Answer:

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b) 0.9826

c) 0.000039308

Step-by-step explanation:

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b) For two minutes, the mean is doubled, hence it is 6. In order to calculate the probability of al least two calls arriving, we calculate first the probability of the complementary event: At most 1 call will arrive. For that probability, we need to sum the probabilities of 0 and 1.

P_X(0) = e^{-6}

P_X(1) = \frac{e^{-6}*6^1}{1!} = 6*e^{-6}

Hence,

P(X \geq 2) = 1-P(X < 2) = 1- 7*e^{-6} = 0.9826

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P_X(0) = e^{-15}

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As a result,

P(X \leq 2) = e^{-15}(1+15+112.5) = 0.000039308

Practically 0

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2 years ago
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