Answer:
The following code are:
public void dissolve() {
setRed(getRed()+1);
setGreen(getGreen()+1);
setBlue(getBlue()+1);
alpha+=1;
}
Explanation:
Here, we define the void type function "dissolve()" inside it, we set three function i.e, "setRed()", "setGreen()", "setBlue()" and then we increment the variable "alpha" by 1.
Inside those three mutators method we set three accessor methods i.e, "getRed()", "getGreen()" , "getBlue()" and increment these accessor by 1.
The values will not be returned by the mutator functions, the accessor will be returned the values.
Answer: C)definition of empirical measures
Explanation: CSIRT(Computer Security Incident Response Team) is the team that is related with the taking the measurement according to the related incident of the security. The tasks that are performed by the team are detection of security error, dealing with it ,introducing ideas to resolve it etc.
Empirical measure is the measure that technique which has randomness. Random measures are the based on the possible methods that can be used for solving the security issue.Thus feedback of CSIRT is effective or not can be seen by the empirical technique.Thus, the correct option is option(c).
c. would be the best answer.
Answer:
x=2
x=1
x=2
Explanation:
a)
This if statement if (1+2=3) checks if the addition of two numbers 1 and 2 is true. Here the addition of 1 and 2 is 3 which is true. So the condition becomes true.
Since the condition is true x:=x+1 statement is executed. This statement means that the value of x is incremented by 1.
The value of x was 1 before the if statement is reached. So x:=x+1 statement will add 1 to that value of x.
x:=x+1 means x=x+1 which is x=1+1 So x=2
Hence value of x is 2 (x=2) after the execution of x:=x+1
b)
In statement b the value of x will be 1 because both the mathematical operations in the if statement evaluate to false.
which means in b, x:=x+1 will not be executed and value of x remains unchanged i.e x=1
In (c) the value x will be 2 because the condition in the if statement is true. Both mathematical expressions 2+3=5 and 3+4=7 are true. Therefore x:=x+1 will be executed and value of x will be incremented by 1. Hence x=2
