1-9 = 9 digits
10-99 = 180 digits
So if we continue the pattern to 99, there are 189 digits, and the last 5 digits would be 79899. Counting backwards: 189th = 9, 188th = 9, 187th = 8, 186th = 9, 185th = 7.
The 185th digit is 7.
Answer:
a) P(identified as containing explosives)=P(actually contains explosives and identified as containing explosives)+P(actually not contains explosives and identified as containing explosives)
=(10/(4*106))*0.95+(1-10/(4*106))*0.005 =0.005002363
hence probability that it actually contains explosives given identified as containing explosives)
=(10/(4*106))*0.95/0.005002363=0.000475
b)
let probability of correctly identifying a bag without explosives be a
hence a =0.99999763 ~ 99.999763%
c)
No as even if that becomes 1 ; proportion of true explosives will always be less than half of total explosives detected,
Answer:
c = 34/d
d = 1/2
Step-by-step explanation:
Part A
Basic Formula
c = k/d
17 = k/2 Multiply both sides by 2
17*2 = k*2/2 Combine
34 = k
So the equation is c = 34/d
Part B
c = 68
k = 34
d = ?
68 = 34/d Multiply both sides by d
68*d = 34 * d/d Simplify.
68 d = 34 Divide by 68
d = 34/68 Simplify
d = 1/2
Answer:
reflected
Step-by-step explanation:
ΔXYZ was dilated, then reflected, to create ΔQAG.
Answer:
There is no error, Amad is correct.
Step-by-step explanation:
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