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vovangra [49]
2 years ago
4

Confidence Interval Concept Check 3 1 point possible (graded) In a new experiment consisting of 150 couples, 75 couples are obse

rved to turn their heads to the left and the remaining 75 couples turned their heads to the right when kissing. Let p denote the (unknown) parameter which specifies the probability that a couple turns their head to the right.
Which of the following statements are correct regarding this experiment? You are given that exactly one but not both of choices 3 and 4 is correct. Also, assume that the given confidence intervals are an instance of a random interval computed upon observing the given data.
10,05] is a 50% asymptotic confidence interval for p. [0.5, 1] is a 50% asymptotic confidence interval for p. 10.466, 0.533 is a 50% asymptotic confidence interval for p. 10.48, 0.52 is a 50% asymptotic confidence interval for p. O
Mathematics
1 answer:
Inessa05 [86]2 years ago
5 0

Answer:

Step-by-step explanation:

There are four options given above.

P specifies the probability that a couple turns their head to the right when kissing. P is 0.5 because the probability of turning right when kissing is 75÷150 = 1/2 = 0.5

Assuming that the given confidence intervals are an instance of a random interval computed upon observing the given data,

The correct statements are statements 1 and 4

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Which are the solutions of x2 = –5x + 8? StartFraction negative 5 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFract
serg [7]

Answer:

x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

Step-by-step explanation:

Given:

The equation to solve is given as:

x^2=-5x+8

Rearrange the given equation in standard form ax^2+bx +c =0, where, a,\ b,\ and\ c are constants.

Therefore, we add 5x-8 on both sides to get,

x^2+5x-8=0

Here, a=1,b=5,c=-8

The solution of the above equation is determined using the quadratic formula which is given as:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plug in a=1,b=5,c=-8 and solve for x.

x=\frac{-5\pm \sqrt{5^2-4(1)(-8)}}{2(1)}\\x=\frac{-5\pm \sqrt{25+32}}{2}\\x=\frac{-5\pm \sqrt{57}}{2}\\\\\\\therefore x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

Therefore, the solutions are:

x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

4 0
2 years ago
Read 2 more answers
An orange is shot up into the air with a catapult. The function h given by h(t)=15+60t-16t^2 models the orange’s height, in feet
Studentka2010 [4]

Complete question is:An orange is shot up into the air with a catapult. The function h given by h(t) = 15 + 60t - 16t² models the orange’s height, in feet, t seconds after it was launched.

Select all the true statements about the situation.

Options:

1. The domain of function h only contains values greater than or equal to 0.

2. The orange is at the same height 1 second after launch and 2 seconds after launch.

3. After 3 seconds, the orange has hit the ground.

4. The orange is 15 feet above the ground when it is launched.

5. The value t = 10 does not belong to the domain of h.

Answer:

Option 1 - True

Option 2 - False

Option 3 - False

Option 4 - True

Option 5 - True

Step-by-step explanation:

Looking at the options,

-The domain is the x or t value and it is time. Now, time can only be positive or greater than or equal to zero i.e. t ≥ 0. Thus, option 1 is true.

- At t = 1 second;

h = 15 + 60(1) - 16(1)²

h = 15 + 60 - 16 = 59 ft

Also, at t = 2 seconds;

h = 15 + 60(2) - 16(2)²

h = 15 + 120 - 64 = 71 ft

So,value of h is not the same at t = 1 and t = 2. Thus, option 2 is not true.

- The orange will hit the ground when h(t) = 0.

However, at t = 3;

h(t) = 15 + 60(3) - 16(3)²

h(t) = 51 ft

h(t) is not equal to zero at t = 3, so option 3 is false

- when the orange is launched it is at time t = 0.

Thus,

h(0) = 15 + 60(0) - 16(0)²

h(0) = 15 ft

So option 4 is true.

- At t=10, h(t) = 15 + 60(10) - 16(10)²

h(10) = -985

This means the orange would be below ground level and thus doesn't belong to the domain of h, so option 5 is true.

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2 years ago
Chris tried to rewrite the expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}(4
crimeas [40]

We have been given an expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}. We have been given steps how Chris tried to solve the given expression. We are asked to choose the correct option about Chris's work.

Let us simplify our given expression.

Using exponent property, a^m\cdot a^n=a^{m+n}, we cab rewrite our given expression as:

\left( 4^{-2+(-3)} \right)^{3}

\left( 4^{-5} \right)^{3}

Now we will use exponent property (a^m)^n=a^{m\cdot n}to further simplify our expression.

\left( 4^{-5} \right)^{3}= 4^{-5\cdot 3}

\left( 4^{-5} \right)^{3}= 4^{-15}

Therefore, Chris made mistake in step 2.

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Triangle A B C is shown with its exterior angles. Line C B extends through point D. Line B C extends to form exterior angle that
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Answer:

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stellarik [79]

Answer should be:

b. No; it is a reflection followed by a translation.

Hope it helps.

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2 years ago
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