Answer:
Explanation:
We have to combine the following formula to find the mass yield:
The diffusion coefficient :
The area :
Time :
ΔC:
Δx:
Now substitute the values
An electric motor M is used to reel in cable and hoist a bicycle into the ceiling space of a garage. Pulleys are fastened to the
1 answer:
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Answer:
a. 4.279 MPa
b. 3.198 MPa to 4.279 MPa
c. 0.939 MPa
d. Below 3.198 MPa
Explanation:
From the given parameters
M = 1.75 MPa
M at 1.6 MPa gives A/A* = 1.2502
M at 1.8 MPa gives A/A* = 1.4390
Therefore, by interpolation, we have M = 1.75 MPa gives A
However, we shall use M = 1.75 MPa and A
Similarly,
P/P₀ = 0.1878
a) Where the nozzle is choked at the throat there is subsonic flow in the following diverging part of the nozzle. From tables, we have
A/A* = 1.387. by interpolation M
Therefore P = P₀ × P
Which shows that the nozzle is choked for back pressures lower than 4.279 MPa
b) Where there is a normal shock at the exit of the nozzle, we have;
M₁ = 1.75 MPa, P₁ = 0.1878 × 5 = 0.939 MPa
Where the normal shock is at M₁ = 1.75 MPa, P₂/P₁ = 3.406
Where the normal shock occurs at the nozzle exit, we have
Where the shock occurs t the section prior to the nozzle exit from the throat, the back pressure was derived as = 4.279 MPa
Therefore the back pressure value ranges from 3.198 MPa to 4.279 MPa
c) At M = 1.75 MPa and P
d) Where the back pressure is less than 3.198 MPa according to isentropic flow relations supersonic flow will exist at the exit plane
Answer:
ΔKE=-347.278 kJ
ΔPE= 441.45 kJ
Explanation:
given:
mass m=900 kg
the gravitational acceleration g=9.81 m/s^2
the initial velocity =100 km/h-->100*10^3/3600=27.78 m/s
height above the highway h=50 m
h1=0m
the final velocity =0 m/s
<u>To find:</u>
the change in kinetic energy ΔKE
the change in potential energy ΔPE
<u>assumption:</u>
We take the highway as a datum
<u>solution:</u>
ΔKE=5*m*(^2-
^2)
=-347.278 kJ
ΔPE=m*g*(h-h1)
= 441.45 kJ