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svetoff [14.1K]
2 years ago
8

Ramiro is also a college student. He has a credit card balance of $500.00. The APR on his card is 18.24%. His minimum payment is

$10.00. (do not use commas or dollar signs in the answers) If Ramiro stops using his credit card, how long will it take him (in months) to pay off the $500.00 if he makes only the minimum payment?
Mathematics
1 answer:
7nadin3 [17]2 years ago
3 0

Answer: It will take approximately 30 months to pay off the $500.00.

Step-by-step explanation:

Since we have given that

Principal = $10.00

Amount = $500.00

Rate of interest = 18.24%

So, we will apply "Compound interest" to find the number of months:

A=P(1+\dfrac{r}{100})^n\\\\500=10(1+\dfrac{18.24}{100})^n\\\\500=11.824^n\\\\\n\approx 2.5

So, the number of months would be

2.5\times 12=30\ months

Hence, it will take approximately 30 months to pay off the $500.00.

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liberstina [14]
To pass it to atmospheres per kilometer you must multiply the value you have by 1000 because one kilometer represents 1000 meters. Therefore the correct answer would be that 0.992 atmospheres (atm) per meter (m) are 992 atmospheres per kilometer. 
6 0
2 years ago
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At a store, apples cost $0.80 $0.80 each and oranges cost $0.95 $0.95 each. Harry buys some apples and oranges and spends $9.55
gregori [183]

Answer:

Harry buys 6 apples and 5 oranges at the store.

Step-by-step explanation:

Given:

Cost of each apples = $0.8

Cost of each oranges = $0.95

Total money spend =$9.55

Number of fruits bought= 11

We need to find the number of apples bought and number of oranges were bought.

Solution:

Let the number of apples bought be 'a'.

Let the number of oranges were bought be 'o'.

Number of fruits bought= 11

So we can say that;

Number of fruits bought is equal to sum number of apples bought and number of oranges were bought.

framing in equation form we get;

a+o=11 ⇒ equation 1

Now we can say that;

Total money spend is equal to number of apples bought multiplied by Cost of each apples plus number of oranges were bought multiplied by Cost of each oranges.

framing in equation form we get;

0.8a+0.95o=9.55 ⇒ equation 2

Now Multiplying equation 1 by 0.8 we get;

0.8(a+o)=0.8\times11

0.8a+0.8o=8.8 ⇒ equation 3

Subtracting equation 3 from equation 2 we get;

0.8a+0.95o-(0.8a+0.8o)=9.55-8.8\\\\0.8a+0.95o-0.8a-0.8o=0.75\\\\0.15o=0.75

Dividing both side by 0.15 we get;

\frac{0.15o}{0.15}=\frac{0.75}{0.15}\\\\o=5

Substituting the value of o in equation 1 we get;

a+o=11\\\\a+5=11\\\\a=11-5=6

Hence Harry buys 6 apples and 5 oranges at the store.

3 0
2 years ago
Given H(6,7) and I(-7,-6), if point G lies 1/2 of the way along line segment HI, Santiago argues that point G is located at the
irinina [24]

Given the points H(6,7) and I(-7,-6).

If point G lies \frac{1}{2} of the way along line segment HI.

Therefore, we can say that the point G divides the line segment HI in the ratio 1:1.

So, by using the cross section formula we can determine the coordinates of point G.

For the given points say (x_1, y_1) and (x_2, y_2) divided is in the ratio m_1 : m_2, the coordinates are (\frac{m_1x_2+m_2x_1}{m_1+m_2} , \frac{m_1y_2+m_2y_1}{m_1+m_2} )

Coordinates G = (\frac{(1 \times -7)+(1 \times 6)}{2} , \frac{(1 \times -6)+(1 \times 7)}{2})

= (-0.5 , 0.5)

Hence, the coordinates of G are (-0.5 , 0.5).

So, Santiago argues that point G is located at the origin. The point G is located at (-0.5, 0.5). Therefore, he is not correct.

8 0
2 years ago
A line passes through the points (15,−13) and (16,−11). Hollis writes the equation y+13=(x−15) to represent the line. Which answ
Andru [333]

The equation formula is y - y1 = m(x-x1)

Using the first point for x1, y1:

Y +13 = m(x-15)

M is the slope which is the change in y over the change in x:

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The equation becomes y +13 =2(x+15)

The answer is:

He incorrectly wrote the slope in his equation. He should have written y+13=2(x−15).

8 0
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USPshnik [31]

Answer:

Eric will win if Nita chooses 7 and he chooses and number that is less than 17 (ex. n<17).

Nita will win if Eric chooses 17 and she chooses a number less than 8 (ex. n<8).

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