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ICE Princess25 [194]
2 years ago
13

A cycle race in France is 2214.5 miles in length. Miguel knows his average speed from previous races is 21.14 miles per hour. Fo

r this next race in France he is planning on cycling 9 hours per day. Estimate how many days Miguel will take to complete the race
Mathematics
1 answer:
tangare [24]2 years ago
8 0

Answer: 12 days

Step-by-step explanation:

Distance = speed / time

2214.50 = 21.14 / t

t = 2214.50 / 21.14 = 104.75 hours

At 9 hours per day, it will take

104.754/9 = 11.64 = 12 days

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Lin plays a game that involves a standard number cube and a deck of ten cards numbered 1 through 10. If both the cube and card h
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1/20, 1 in 20 turns,...............
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The students in the service club are mixing paint to make a mural. The table below shows the different parts of paint that the s
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There are really only two different shades of what I think is pink.

1/3 is equal to 2/6 which is equal to 3/9

1/2 is equal to 2/4 which is equal to 4/8

The bolded ones are the original mixtures given.

Start with 1/3 Multiply top and bottom by 2 and you get 2/6

When you multiply top and bottom of 1/3 by by 3 you get 3/9

Use the same idea for 1/2

6 0
2 years ago
Taxes on the property buyer Tamara is purchasing are $8,200, due on December 31. If the closing is set for June 29th, using the
rosijanka [135]

The buyer will be paying taxes for 185 days, so will pay

... (185/365)·$8200 = $4156

Your most appropriate choice seems to be $4178, which corresponds to 186 days' taxes.

_____

There are 30 days in each month in the last half of the year, plus 1 additional day in each of July, August, October, and December. The 30th of June also belongs to the buyer (but the 29th, closing day, does not), so there are 180+5 = 185 days for which the buyer must pay taxes. The answer choices don't include that value.

3 0
2 years ago
What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

4 0
2 years ago
Read 2 more answers
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