A function that models the profit for a new pet-monitoring system shows that there is no profit made until the price reaches
2 answers:
Answer:
The graph that best fits this model of profit and price per unit is attached to this solution.
Step-by-step explanation:
A couple of graphs are missing from the question. According to the full question as obtained online, there are a number of graph options, and we are expected to pick the best option. I would not add all the other graphs to limit the chances of deletion due to violating community guidelines.
The function is to model the profits of a new pet-monitoring system, so, if the profits are y and x is the price per unit, y = f(x)
The profits vary as the price per unit varies, there is no profit made until the price reaches
$95 per unit, a maximum profit at a price of $140 per unit, and no profit at a price over $185 per unit.
This description of the curve shows that y is negative at values of x less than $95, then the profits increase when x varies between $95 and $140. The profits reach a maximum at $140 and then the profits start to decline as x increases again, the profits go to 0 at x = $185.
This description shows that the function is a quadratic function with a graph that is n-shaped, peaking at x=185 and the graph crosses the x-axis at x=95 and x=185.
The most fitting graph for this model is attached to this solution provided.
From the graph, all the descriptions above are evident.
Hope this Helps!!!
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Answer:
0.25
Step-by-step explanation:
72% of courses have final exams and 46% of courses require research papers which means probability of 0.72 for courses that have final exams and 0.46 for courses that require research papers.
31% of courses have a research paper and a final exam, which means probability of 0.31 for both courses with exams and research papers, using Venn diagram approach, find picture attached to the solution.
P(R or E) = P(R) + P(E) - P(R and E), which gives:
P(R or E) = 0.15 + 0.41 - 0.31
P(R or E) = 0.25.
Answer:
1
The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial
2
The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population
3
4
The p-value is
5
The conclusion is
There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial
The test statistics is
Step-by-step explanation:
From the question we are told that
The first sample size is
The first sample mean is
The second sample size is
The second sample size is
The first standard deviation is
The second standard deviation is
The level of significance is
The null hypothesis is
The alternative hypothesis is
Generally the test statistics is mathematically represented as
=>
=>
The p-value is mathematically represented as
Generally from the z table
=>
From the values obtained we see that so the null hypothesis is rejected
Thus the conclusion is
There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial