With methyl, ethyl, or cyclopentyl halides as your organic starting materials and using any needed solvents or inorganic reagent
s, outline syntheses of each of the following. More than one step may be necessary and you need not repeat steps carried out in earlier parts of this problem. (a) CH3I (b) I (c) CH3OH (d) OH (e) CH3SH (f) SH (g) CH3CN (h) CN (i) CH3OCH3 (j) OMe
1 answer:
Answer:
In the attachment you can find all the possible chemical reactions.
Some reaction can not be obtained by using alkyl halides because halides are weak leaving group which can leave compound during reaction easily but hydroxyl groups is a strong nucleophile which can not leave compound easily. So we can obtain alcohol from ethyl bromide, but we can not obtain hydroxyl ion from ethyl bromide.
Explanation:
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Answer:
Here's what I get
Explanation:
(g) Titration curves
I can't draw two curves on the same graph, but I can draw two separate curves for you.
The graph in part (d) had an equivalence point at 20 mL.
In the second titration, the NaOH was twice as concentrated, so the volume to equivalence point would be half as much — 10 mL.
The two titration curves are below.
(h) Evidence of reaction
HCl and NaOH are both colourless.
They don't evolve a gas or form a precipitate when they react.
The student probably noticed that the Erlenmeyer flask warmed up — a sign of a chemical change.
Answer:
8.0 moles
Explanation:
Since the acid is monoprotic, 1 mole of the acid will be required to stochiometrically react with 1 mole of NaOH.
Using the formula:
Concentration of acid = ?
Volume of acid = 10 mL
Concentration of base = 1.0 M
Volume of base = 40 mL
mole of acid = 1
mole of base = 1
Substitute into the equation:
Concentration of acid = 40/10 = 4.0 M
To determine the number of moles of acid present in 2.0 liters of the unknown solution:
Number of moles = Molarity x volume
molarity = 4.0 M
Volume = 2.0 Liters
Hence,
Number of moles = 4.0 x 2.0 = 8 moles