The answer is 20 days.
After 60 people have joined there will be 460 people in the camp.
The number of days which the provisions will last will be proportional less after the 60 people have joined and will be:-
(400/460) * 23
= (20 / 23) * 23
= 20
Answer:
Step-by-step explanation:
step 1
Find the value of x
we know that
r is the midpoint of qs
so
QR=RS
QS=QR+RS------> QS=2RS -----> equation A
RT=RS+ST ----> equation B
see the attached figure to better understand the problem
Substitute the given values in the equation B and solve for x
step 2
Find the value of RS
substitute the value of x
step 3
Find the value of QS
Remember equation A
QS=2RS
so
Answer: The length of segments between this point and the vertices of greater base are 
and 18.
Step-by-step explanation:
Let ABCD is the trapezoid, ( shown in below diagram)
In which AB is the greater base and AB = 18 DC= 11, AD= 3 and BC = 7
Let P is the point where The extended legs meet,
So, according to the question, we have to find out : AP and BP
In Δ APB and Δ DPC,
∠ DPC ≅ ∠APB ( reflexive)
∠ PDC ≅ ∠ PAB ( By alternative interior angle theorem)
And, ∠ PCD ≅ ∠ PBA ( By alternative interior angle theorem)
Therefore, By AAA similarity postulate,
Let, DP =x
⇒ 
⇒ 33 +11x = 18x
⇒ x = 33/7= 
Thus, PD=
But, AP= PD + DA
AP= 
Now, let PC =y,
⇒ 
⇒ 77 + 11y = 18y
⇒ y = 77/7 = 11
Thus, PC= 11
But, PB= PC + CB
PB= 11+7 = 18
Area of parallelogram = base * height
base 1 = 4.2 cm
height 1 = 3.6 cm
∴ Area = 4.2 * 3.6 = 15.12
let the other base 2 = x
∴ the altitude of this base = height 2 = 2.4
∴Area = 2.4 x = 15.12
Solve for x
∴ x = 6.3 cm
∴ The perimeter of parallelogram = 2( base 1 + base 2)
= 2 ( 4.2 + 6.3 ) = 21 cm
The answer is 141.35 ft²
Before the first break, it was painted:
150 ft² ÷ 2 = 75 ft²
Now it's left:
150 ft² - 75 ft² = 75 <span>ft²
Before the second break, it was painted:
75 </span>ft² ÷ 2 = 37.5 <span>ft²
Now it's left:
75 </span>ft² - 37.5 ft² = 37.5 <span>ft²
Before the third break, it was painted:
37.5 </span>ft² ÷ 2 = 18.75 <span>ft²
</span><span>Now it's left:
</span>37.5 ft² - 18.75 ft² = 18.75 <span>ft²
</span>
<span>Before the fourth break, it was painted:
</span>18.75 ft² ÷ 2 = 9.375 <span>ft²
</span><span>Now it's left:
</span>18.75 ft² - 9.375 ft² = 9.375 <span>ft²
</span>
<span>Before the fourth break, it was painted:
</span>9.375 ft² ÷ 2 = 4.6875 <span>ft²
</span><span>Now it's left:
</span>9.375 ft² - 4.6875 ft² = 4.6875 ft²
Now, we will sum what he painted for now:
75 ft² + 37.5 ft² + 18.75 ft² + 9.375 ft² 4.6875 ft² = 141.3125 ft² ≈ 141.35 ft²
When the painter takes his fifth break, there will be <span>141.35 ft² of the wall painted.</span>
