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2 years ago

Share £40 in the ratio 1:4 between Tim and Sam

Mathematics

2 answers:

lesantik [10]2 years ago

7 0

Answer:

$\£8:\£32$

Step-by-step explanation:

$\frac{40}{1+4}$

$\frac{40}{5}$

$=8$

$1:4$

$1 \times 8:4 \times 8$

$8:32$

svetoff [14.1K]2 years ago

6 0

Answer:

Tim gets £8

Sam gets £32

Step-by-step explanation:

Ratio is 1:4

So, Total parts are 1+4 = 5

Dividing it by total parts

= $\frac{40}{5}$

= £ 8

So, Tim gets £8

But,

Sam gets 4(£8)

= Sam gets £32

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2 years ago

What is the cube root of -729a9b6

Harman [31]

<u>ANSWER</u>

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = - 9 {a}^{3} {b}^{2}$

<u>EXPLANATION</u>

We want to find the cube root of

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We express this symbolically as:

$\sqrt[3]{- 729 {a}^{9} {b}^{6} }$

The expression under the radical called the radicand.

We need to express this radical in exponential form using the property,

${x}^{ \frac{m}{n} } = \sqrt[n]{ {x}^{m} }$

Applying this rule gives us:

$\sqrt[3]{- 729 {a}^{9} {b}^{6} } = ({- 729 {a}^{9} {b}^{6}})^{ \frac{1}{3} }$

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = ({- {9}^{3} {a}^{9} {b}^{6}})^{ \frac{1}{3} }$

Recall that

$({a}^{m} )^{n} = {a}^{mn}$

We apply this rule on the RHS to get,

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = ({- {9}^{3 \times { \frac{1}{3} } } {a}^{9 \times { \frac{1}{3} } } {b}^{6 \times { \frac{1}{3} } }})$

This simplifies to

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = - 9 {a}^{3} {b}^{2}$

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