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nasty-shy [4]
2 years ago
13

Raj and Nicole's polynomial expressions are added to create a sum, written in standard form. What can you determine about the de

gree of the sum? The sum will be degree . What can you determine about the number of terms of the sum? The maximum number of terms of the sum is , but it could be less.
Mathematics
1 answer:
Lesechka [4]2 years ago
6 0

Complete question is;

raj writes a polynomial expression in standard form using one variable, a, that has 4 terms and is degree 5. Nicole writes a polynomial expression in standard form using one variable, a, that has 3 terms and is degree 2. Raj and Nicole’s polynomial expressions are added to create a sum, written in standard form. What can you determine about the degree of the sum? The sum will be degree . What can you determine about the number of terms of the sum? The maximum number of terms of the sum is , but it could be less.

Answer:

Degree: 5

Maximum number of terms: 6 or could less

Step-by-step explanation:

We are told that Raj writes a polynomial expression in standard form using one variable, a, that has 4 terms and is degree 5. So let this polynomial be: Aa^(5) + Ba³ + Ca + D

Also, we're told that: Nicole writes a polynomial expression in standard form using one variable, a, that has 3 terms and is degree 2.

The polynomial is: Ea² + Fa + G

If we add both polynomials we, we will get;

Aa^(5) + Ba³ + Ca + D + Ea² + Fa + G

Rearranging terms to give;

Aa^(5) + Ba³ + Ea² + Ca + Fa + D + G

Collecting like terms to give;

Aa^(5) + Ba³ + Ea² + a(C + F) + (D + G)

So this is now a 5 degree polynomial.

So the new sum will have a degree of 5.

Also, as seen in the above steps, the maximum number of terms could be 6 or less.

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for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8

2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24

3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75

4th
average betwen 1.5 and 2 is 1.75
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0.4 times 1.74=0.7

add them all up
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8 0
2 years ago
The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit in
Marina86 [1]

Answer:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3

We can express this formula like this:

\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2

\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

If we operate and we take out the 1/4 as a factor we got this:

\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}

We can cancel n^2 and we got

\lim_{n\to\infty} \frac{(n+1)^2}{n^2}

We can reorder the terms like this:

\lim_{n\to\infty} (\frac{n+1}{n})^2

We can do some algebra and we got:

\lim_{n\to\infty} (1+\frac{1}{n})^2

We can solve the square and we got:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

3 0
2 years ago
The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2
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-- Reflecting across the x-axis makes all the x-coordinates the negative of
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-- Translating 2 units up makes all the y-coordinates 2 greater than
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You didn't give us a list of new coordinates, so there's nothing
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8 0
2 years ago
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Ghella [55]

Answer: find the answers in the explanation.

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2.) The unit of the slope of the line is text per year

3.) Therefore, the slope of the line tells you that for every year older the smart phone user is, you can expect a typical average in text messages sent of - 0.8

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4 0
2 years ago
One month julia collected 8.4 gallons of rainwater. That month she used 5.2 gallons of rainwater to water her garden and 6.5 gal
Andru [333]

Given

One month julia collected 8.4 gallons of rainwater.

she used 5.2 gallons of rainwater to water her garden

6.5 gallons of rainwater to water flowers

Find out how much was the supply of rainwater increased or decreased by the end of the month.

To proof

As given in the question

One month julia collected 8.4 gallons of rainwater

she used 5.2 gallons of rainwater to water her garden and 6.5 gallons of rainwater to water flowers

Total water she used in the month = 5.2 gallons + 6.5gallons

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Let the supply of rainwater increased or decreased by the end of the month

be x .

Than the equation become in the form

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x = 3.3 gallons

Therefore the supply of rainwater increased or decreased by the end of the month is 3.3 gallons.

Hence proved



8 0
2 years ago
Read 2 more answers
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