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Burka [1]
2 years ago
9

Maria, Max, Molly, and Mitch are all picking apples at an orchard. The number of apples Max picks is the number of apples Maria

picks squared. Molly picks the number of apples that Max and Maria pick combined. Mitch picks the number of apples Molly picks squared plus the number of apples that Maria picks. If Maria picks 3 apples, then how many apples does Mitch pick
Mathematics
1 answer:
irinina [24]2 years ago
3 0

Answer:

147

Step-by-step explanation:

Given: Maria=3

Max=3 squared=9

Molly=Max+Maria=9+3=12

Mitch=Molly squared+Maria=144+3=147

Hope this helps!

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An engineering school reports that 53% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A)
erik [133]

Answer: Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

                      18-20                  Not 18-20           Total

Male                0.23                    0.35                 0.58

Female            0.16                     0.26                0.42

Total                0.39                    0.61                   1

P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)

P(female or between 18-20) =  0.42+0.39-0.16

P(female or between 18-20) = 0.65

Hence, our required probability is 0.65.

3 0
2 years ago
Please consider the following data set. The initial row provides labels for two variables (i.e., X1 and X2). Each subsequent row
LekaFEV [45]

Answer:

There is no significant difference between the means.

Step-by-step explanation:

Given is the data set for X1 and x2 are we have to do a paired t test.

H_0: \bar X_1 = \bar X_2\\H_a: \bar X_1 \neq \bar X_2

(Two tailed test at 5% significance level)

Mean difference = 1.00

Std error for difference = 1.225

df=4

Test statistic = mean diff/se = 1.826

p value =0.142

Since p >0.05 our alpha we accept H0

There is no significant difference before and after averages at 5% sign. level.

3 0
2 years ago
Zach walked his dog for 7/8 hour. They spent 1/2 of the time at the beach. How much time did Zach and his dog spend at the beach
Tresset [83]

Answer: \frac{7}{16}hour

Step-by-step explanation:

You know that the total time was: 7/8 hour

You also know that they spent 1/2 of the time at the beach.

Therefore, to calculate the time  Zach and his dog spend at the beach (which you can call x) , you must multiply both fractions (7/8 and 1/2).

Then, you obtain the following result:

x=\frac{7}{8}hour*\frac{1}{2}\\\\x=\frac{7}{16}hour

5 0
2 years ago
Sophie has $4.20 worth of dimes and quarters. She has twice as many quarters as
ikadub [295]

Answer:

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The average time taken to complete an exam, X, follows a normal probability distribution with mean = 60 minutes and standard dev
k0ka [10]

Answer: b. 0.8413

Step-by-step explanation:

Given : The average time taken to complete an exam, X, follows a normal probability distribution with \mu=60\text{ minutes} and \sigma=30\text{ minutes} .

Then, the  probability that a randomly chosen student will take more than 30 minutes to complete the exam will be :-

P(x>30)=P(z>\dfrac{30-60}{30})\ \ [\because\ z=\dfrac{x-\mu}{\sigma} ]\\\\=P(z>-1)=P(z-z)=P(Z

 [using z-value table]

Hence, the probability that a randomly chosen student will take more than 30 minutes to complete the exam =  0.8413

3 0
2 years ago
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