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2 years ago

14

A quantity with an initial value of 8600 grows exponentially at a rate of 20% every 2 minutes. What is the value of the quantity

after 67 minutes, to the nearest hundredth?

1 answer:

Hatshy [7]2 years ago

3 0

Answer:

23400 x 8/100 = 1872 = the loss

1872 : 12 = 156= the loss each month

156/1872*100% = 8.33 % then round it

You might be interested in

Natalia solved the problem 74.4/12=6.2. complete the model with partial products check Natalia's work using multiplication

tia_tia [17]

Answer:

Natalia's work is wrong.

Step-by-step explanation:

Natalia divided a decimal number by an entire number. Since division is a operation derived from multiplication, the best approach to check if work was good is multiplying the given result by denomination, that is:

1) $x = 6.2\times 12$ Given.

2) $x = \left(6+0.2\right)\times 12$ Definition of addition.

3) $x = 6\times 12 + 0.2\times 12$ Distributive property.

4) $x = 72 + \frac{2}{10}\times 12$ Definitions of multiplication and decimal number.

5) $x = 72 +[2\cdot (10)^{-1}]\cdot 12$ Definition of division/Associative property.

6) $x = 72 + [2\cdot 12]\cdot (10)^{-1}$ Associative property.

7) $x = 72 + 24\cdot 10^{-1}$ Definition of multiplication.

8) $x = 72 + \frac{24}{10}$ Definition of divsion.

9) $x = 72 + 2.4$ Defintion of decimal number.

10) $x = 74.4$ Definition of addition/Result

Natalia's work is wrong.

5 0

2 years ago

Drag each tile to the correct box.

Umnica [9.8K]

Answer:

Emma ⇒ IQR = 3.5

Sally ⇒ IQR = 3

Olivia ⇒ IQR = 2.5

Emma - Sally - Olivia

Step-by-step explanation:

Emma's Scores:

<u>6 , 7 , 8 , 8 , </u><u>9 , 9</u><u> , 9 , 10 , 10 , </u><u>11</u> , <u>11</u><u> , 11 , 11 , 11 , </u><u>12 , 13</u><u> , 13 , 13 , 13 , 14</u>

LQ = (9 + 9) ÷ 2 = 9

UQ = (12 + 13) ÷ 2 = 12.5

IQR = 12.5 - 9 = 3.5

Sally's Scores:

<u>6 , 6 , 6 , 7 , </u><u>7 , 8</u><u> , 8 , 8 , 9 , </u><u>9</u> , <u>10</u><u> , 10 , 10 , 10 , 10</u><u> , 10 , 11</u><u> , 11 , 12 , 12 , 14</u>

LQ = (7 + 8) ÷ 2 = 7.5

UQ = (10 + 11) ÷ 2 = 10.5

IQR = 10.5 - 7.5 = 3

Olivia's Scores:

<u>6 , 6 , 7 , 7 , </u><u>7 , 8</u><u> , 8 , 8 , 8 , </u><u>9</u> , <u>9</u><u> , 9 , 9 , 9 , </u><u>10 , 10</u><u> , 12 , 12 , 13 , 14</u>

LQ = (7 + 8) ÷ 2 = 7.5

UQ = (10 + 10) ÷ 2 = 10

IQR = 10 - 7.5 = 2.5

Emma - Sally - Olivia

6 0

2 years ago

Read 2 more answers

A farmer plants corn in 1/4 of his field. He plants white corn in 3/5 of the corn

bija089 [108]

Answer:

$\frac{3}{20}$

Step-by-step explanation:

Fraction of the total that is for corn (TC - Total corn):

$TC=\frac{1}{4}$

fraction of the corn section that is for white corn (WC - white corn in the corn seccion):

$WC=\frac{3}{5}$

we need to find the fraction of the whole field that is for the white corn.

For this we need to find how much is $\frac{3}{5}$ out of the $\frac{1}{4}$ destinated to corn, and this will be the fraction of the total that is for white corn. We find this fraction by multiplying the fraction of corn ( $\frac{1}{4}$ ) by the fraction of white corn in the corn section ( $\frac{3}{5}$ ).

I will call the total fraction of white corn TWC, thus:

$TWC=WC*TC=\\=\frac{3}{5} *\frac{1}{4} \\\\=\frac{3*1}{5*4} \\\\=\frac{3}{20}$

the answer is: $\frac{3}{20}$ of the whole field is planted with white corn

5 0

2 years ago

A glass bead has the shape of a rectangular prism with a smaller rectangular prism removed. What is the volume of the glass that

olganol [36]

The volume of the removed portion is 35 cm³.

Step-by-step explanation:

Given,

The length× width× height (L×B×H) of the outer part = 3 cm×3 cm×7 cm

The length× width× height (l×b×h) of the inner part = 2 cm×2 cm×7 cm

To find the volume of the removed portion.

Formula

The volume of the removed portion = volume of outer part - volume of inner part

Volume of rectangular prism = l×b×h

Now,

Volume of outer part = 3×3×7 cm³ = 63 cm³

Volume of inner part = 2×2×7 cm³ = 28 cm³

Hence,

The volume of the removed portion = 63-28 cm³ = 35 cm³

4 0

2 years ago

Read 2 more answers

2.5 kg of cabbages cost £1.20<br><br> Work out the cost of 3.75 kg

s2008m [1.1K]

Thank you for your question!

In order to get the cost of 1 kg of cabbage, divide the cost by the quantity:

1.20/2.5
0.48

Now, multiply the amount for 1 kg to 3.75, because you need 3.75 times the amount.

0.48 * 3.75
1.80

So, it would cost 1.80 pounds for 3.75 kg.
Hope this helped!

8 0

2 years ago