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NISA [10]
2 years ago
7

Write a C++ program that uses a while statement and the tab escape sequence \t to print the following table of values:N 1 0*N 1

00*N 1 000*N1 1 0 1 00 1 0002 20 200 20003 30 300 30004 40 400 4000
5 50 500 5000
Computers and Technology
1 answer:
Luda [366]2 years ago
5 0

Answer:

#include <iostream>

using namespace std;

int main()

{

cout << "N\t10*N\t100*N\t1000*N" << endl;

int x=1;

while(x<=5){

 cout << x <<"\t"<< x*10 <<"\t"<<x*100  <<"\t"<< x*1000 << endl;

 x++;

}

   return 0;

}

Explanation:

Print the header, N 10*N 100*N 1000*N, using \t

Initialize the x as 1. It will be used to control the while loop

Create a while loop that iterates while x is smaller than or equal to 5

Inside the loop, print the required values. After printing, increment the value of x by 1

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Answer:

see explaination

Explanation:

For GBN:

A sends will 9 segments in total. These are initially sent segments 1, 2, 3, 4, 5 and later re-sent segments 2, 3, 4, and 5.

B will send 8 ACKs. They are 4 ACKS with sequence number 1, and 4 ACKS withsequence numbers 2, 3, 4, and 5.

For SR:

A sends 6 segments in total. They are initially sent segments 1, 2, 3, 4, 5 and later re-sent segments 2. B sends 5 ACKs. They are 4 ACKS with sequence number 1, 3, 4, 5. And there is oneACK with sequence number 2.

For TCP:

A sends 6 segments in total. They are initially sent segments 1, 2, 3, 4, 5 and later re-sent segments 2. B sends 5 ACKs. They are 4 ACKS with sequence number 2. There is one ACK withsequence numbers 6.

Let it be observed that TCP always send an ACK with expected sequencenumber.

b). TCP. This is because TCP uses fast retransmit without waiting until time out.

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Design an application for Bob's E-Z Loans. The application accepts a client's loan amount and monthly payment amount. Output the
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Answer:

part (a).

The program in cpp is given below.

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   //variables to hold balance and monthly payment amounts

   double balance;

   double payment;

   //user enters balance and monthly payment amounts

   std::cout << "Welcome to Bob's E-Z Loans application!" << std::endl;

   std::cout << "Enter the balance amount: ";

   cin>>balance;

   std::cout << "Enter the monthly payment: ";

   cin>>payment;

   std::cout << "Loan balance: " <<" "<< "Monthly payment: "<< std::endl;

   //balance amount and monthly payment computed

   while(balance>0)

   {

       if(balance<payment)    

         { payment = balance;}

       else

       {  

           std::cout << balance <<"\t\t\t"<< payment << std::endl;

           balance = balance - payment;

       }

   }

   return 0;

}

part (b).

The modified program from part (a), is given below.

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   //variables to hold balance and monthly payment amounts

   double balance;

   double payment;

   double charge=0.01;

   //user enters balance and monthly payment amounts

   std::cout << "Welcome to Bob's E-Z Loans application!" << std::endl;

   std::cout << "Enter the balance amount: ";

   cin>>balance;

   std::cout << "Enter the monthly payment: ";

   cin>>payment;

   balance = balance +( balance*charge );

   std::cout << "Loan balance with 1% finance charge: " <<" "<< "Monthly payment: "<< std::endl;

   //balance amount and monthly payment computed

   while(balance>payment)

   {

           std::cout << balance <<"\t\t\t\t\t"<< payment << std::endl;

           balance = balance +( balance*charge );

           balance = balance - payment;

       }

   if(balance<payment)    

         { payment = balance;}          

   std::cout << balance <<"\t\t\t\t\t"<< payment << std::endl;

   return 0;

}

Explanation:

1. The variables to hold the loan balance and the monthly payment are declared as double.

2. The program asks the user to enter the loan balance and monthly payment respectively which are stored in the declared variables.  

3. Inside a while loop, the loan balance and monthly payment for each month is computed with and without finance charges in part (a) and part (b) respectively.

4. The computed values are displayed for each month till the loan balance becomes zero.

5. The output for both part (a) and part (b) are attached as images.

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Answer:

The answer is d. Data

Explanation:

information gathered from observing a plant grow 3 cm over a two-week period results in Data

data is facts and statistics collected together for reference or analysis.

Data is any information that has been collected, observed, generated or created to validate original research findings

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This is the recorded history of the development of a group functioning within an organization. Identify the sentence that refers to the norming stage of group development.

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