Answer:(Answers may vary.)
I researched about different concepts regarding statute of limitations, disclaimers, and filing procedures regarding copyright issues.
Statute of limitations
Statute of limitations for copyright falls under two categories. The first is a limitation for ‘Criminal Proceedings’. In this case, the statute stands that the claim (or lawsuit) has to be filed within five years of the cause (act of infringement). The second consideration is in the ‘Civil Action’ case. Here the claim (lawsuit) has to be filed within three years of the cause. Many times the last act of infringement is taken as the date from which these five (or three) years are calculated. There have been cases where the date when the infringement was discovered by the victim, is taken as a starting date.
Disclaimers
A disclaimer is a statement that is intended to pass on some information about the content of the design to the viewer. This disclaimer may be to signify the intent of the designer behind the content. It may also be a suggestion or warning to ensure the viewer uses discretion while viewing the content. A disclaimer is mutual understanding between the designer and viewer. This would protect the designer rights in a situation where the viewer claims damages after the viewer clearly disregarded the disclaimer.
Filing procedures
A claim for copyright has to be filed (ideally) before any infringement occurs, or within three months of the infringement. Timely registration would help the claim for damages. I can file for a copyright online (U.S. Copyright Office). I can also file for a copyright in printed form at the U.S. Copyright Office. I would need two copies of my work at the time of filing. The online facility is charged (fees) lesser than direct submission. I would have to sure which form I fill, as all the forms refer to different types of work.
Explanation: I just did it and it showed me.
Answer:
num_guesses = int(input())
user_guesses = []
for i in range(num_guesses):
x = int(input())
user_guesses.append(x)
print(user_guesses)
Explanation:
This solution is provided in Python
This line prompts the user for a number of guesses
num_guesses = int(input())
This line initializes an empty list
user_guesses = []
This loop lets user input each guess
for i in range(num_guesses):
This line takes user input for each guess
x = int(input())
This appends the input to a list
user_guesses.append(x)
This prints the user guesses
print(user_guesses)
Answer:
Following are the correct code to this question:
short_names=['Gus','Bob','Zoe']#defining a list short_names that holds string value
print (short_names[0])#print list first element value
print (short_names[1])#print list second element value
print (short_names[2])#print list third element value
Output:
Gus
Bob
Zoe
Explanation:
- In the above python program code, a list "short_names" list is declared, that holds three variable that is "Gus, Bob, and Zoe".
- In the next step, the print method is used that prints list element value.
- In this program, we use the list, which is similar to an array, and both elements index value starting from the 0, that's why in this code we print "0,1, and 2" element value.
<span>Frames have more information in them than bits.
</span>
<span>Frames are made up of bits but not vice versa.
A bit (BInary digiT) is the basic unit of digital. It can be 0 (logical false, off) or 1 (not logical false - true, on). Four bits are in a nybble, which can have a value of 0 - 15, eight bits are in a byte which can have a value of 0 - 255. Words vary in size, they consist of multiple bytes and are generally correlated with the system's data bus/processor data width (a 64 bit system has an 8 byte word).
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Answer:
// program in C++ to check leap year.
// include header
#include<iostream>
using namespace std;
// main function
int main() {
// variable
int inp_year ;
// ask user to enter year
cout<<"Enter year:";
// read year
cin>>inp_year;
// check year is leap or not
if (((inp_year % 4 == 0) && (inp_year % 100 != 0)) || (inp_year % 400 == 0))
// if leap year , print leap year
cout<<inp_year<<" is a leap year.";
else
// print not leap year
cout<<inp_year<<" is not a leap year.";
return 0;
}
Explanation:
Read year from user.Then check if year is divisible by 4 and not divisible by 100 or year is divisible by 400 then year is leap year.otherwise year is not leap year.
Output:
Enter year:1712
1712 is a leap year.