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2 years ago

The pedigree below tracks Duchenne Muscular Dystrophy (DMD) through several generations. DMD is an X-linked recessive trait.

Biology

1 answer:

Goshia [24]2 years ago

3 0

Answer:

- If individual III-1 marries an unaffected, non-carrier female, none of their children will have DMD

Explanation:

From the options, the only correct statements is that <em>If individual III-1 marries an unaffected, non-carrier female, none of their children will have DMD</em>

<u>DMD is an X-linked recessive trait, meaning that a male individual is either affected or unaffected (can never be a carrier). III-1 is unaffected and if he marries an unaffected, non-carrier female, it means that none of their children will have DMD.</u>

All the children of II-4 and II-5 will always come out with DMD because both parents are affected.

Individuals I-1 and II-1 are males. A male can never be a carrier in for X-linked traits. He is either affected or unaffected and as shown by the pedigree, both males are unaffected (unshaded).

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1. The phrase Darwin used to describe his broad theory of evolution is ''descent with modification.

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Two autosomal genes, J and K, are 60 map units apart. You perform the following testcross: J K / j k x j k / j k. At what freque

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Answer:

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%

Explanation:

To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.

The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.

So, en the exposed example:

J and K are autosomal genes

J and K are separated by 60 M.U.

60 M.U. means that there is 60% of recombination.

Cross) J K / j k x j k / j k

Gametes) JK Parental jk, jk, jk, jk

jk Parental

Jk Recombinant

jK Recombinant

One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.

1 M.U. -------------- 1% recombination

60 M.U. ------------ 60% recombination

30% Jk + 30% jK

100 M.U. - 60 M.U. = 40 M.U.

40M.U.--------------40 % Parental (Not recombinant)

20% JK + 20% jk

Punnet Square) JK jk Jk jK

jk JK/jk jk/jk Jk/jk jK/jk

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%

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Answer:

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Explanation:

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Answer:

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