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Andre45 [30]
2 years ago
3

Five companies employed 2340, 3455, 675, 960 and 1350 workers. The first company laid off 1 worker for every 5 workers, while th

e other three recruited 2 new workers for every 3. a) What was the total number of workers at the beginning c) How many people: i) Lost job ii) Got job d) What was the total number of workers finally
Mathematics
1 answer:
Alenkasestr [34]2 years ago
8 0

Answer:

a) 8780

c) i) 1159

   ii) 1990

d) 9611

Step-by-step explanation:

a) What was the total number of workers at the beginning

Solution:

Total number of workers at the beginning

= 2340 + 3455 + 675 + 960 + 1350

= 8780

c) How many people: i) Lost job

Solution:

The first company laid off 1 worker for every 5 workers,

Workers employed were 2340 and 1 worker laid for every 5 workers. So,

2340/5 = 468

Hence 468 lost job in first company.

If you see the statement while the other three recruited 2 new workers for every 3. Assuming that the first two companies laid off 1 worker for every 5 workers, then for the second company:

Workers employed were 3455 and 1 worker laid for every 5 workers. So,

3455 / 5 = 691

Hence 468 lost job in second company.

Now total workers that lost job:

468 + 691 = 1159

ii) Got job

Solution:

As the other three companies recruited 2 new workers for every 3. Thus the number of people who got job in these three companies are:

= (675 * 2 + 960 *2 + 1350 *2) / 3

= (1350 + 1920 + 2700) / 3

= 5970 / 3

= 1990

Hence 1990 people got the job.

d) What was the total number of workers finally

Solution:

Total number of workers:

8780 number of workers at the beginning

1159 from companies who lost job

1990 from companies who got job

So adding the workers who got job in the workers at beginning and subtracting the workers who lost job we get:

total number of workers finally:

= 8780 + 1990 - 1159

= 9611

Hence total number of workers finally are 9611.

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