Given : tan 235 = 2 tan 20 + tan 215
To Find : prove that
Solution:
tan 235 = 2 tan 20 + tan 215
Tan x = Tan (180 + x)
tan 235 = tan ( 180 + 55) = tan55
tan 215 = tan (180 + 35) = tan 35
=> tan 55 = 2tan 20 + tan 35
55 = 20 + 35
=> 20 = 55 - 35
taking Tan both sides
=> Tan 20 = Tan ( 55 - 35)
=> Tan 20 = (Tan55 - Tan35) /(1 + Tan55 . Tan35)
Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1
=> Tan 20 = (Tan 55 - Tan 35) /(1 + 1)
=> Tan 20 = (Tan 55 - Tan 35) /2
=> 2 Tan 20 = Tan 55 - Tan 35
=> 2 Tan 20 + Tan 35 = Tan 55
=> tan 55 = 2tan 20 + tan 35
=> tan 235 = 2tan 20 + tan 215
QED
Hence Proved
They are called invertebrats
Based on the given figure above, we can conclude that the triangle is an isosceles triangle. By definition, an isosceles triangle is a triangle that has at least two equal sides. Since this is an isosceles triangle, 8x-10 =6x. Now we can solve for x. So,
8x-10 =6x
8x-6x = 10
2x =10
x= 5.
Therefore, the value of x in the figure is 5. Hope this is the answer that you are looking for.
Answer:
Histogram.
Step-by-step explanation:
Such a Graph is called Histogram.
A histogram can be defined as a visual representation of data in form of bars of different heights. In histogram, each and every bar groups numbers into ranges. The greater the height of the bar, the larger the data falls into its range. It basically represents shape and spread of continuous data sample.
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Answer:
∛(2500π)√37 m² ≈ 120.911 m²
Step-by-step explanation:
If the height is 3 times the diameter, it is 6 times the radius. Then the volume is ...
V = 1/3πr²h
V = 1/3πr²(6r) = 2πr³
For a volume of 100 m³, the radius is ...
100 m³ = 2πr³
r = ∛(50/π) m
The lateral area of the cone is computed from the slant height. For this cone, the slant height is found using the Pythagorean theorem:
s² = r² +(6r)² = 37r²
s = r√37
Then the lateral area is ...
LA = πrs
LA = π(∛(50/π) m)(∛(50/π) m)√37
LA = ∛(2500π)√37 m² ≈ 120.911 m²
