The lengths of a particular snake are approximately normally distributed with a given mean Mu = 15 in. and standard deviation Si
2 answers:
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Answer:
Step-by-step explanation:
Given that a cola-dispensing machine is set to dispense a mean of 2.02 liters into a bottle labeled 2 liters.
Std deviation =0.015 litres
X- litres contained in a bottle is N(2.02, 0.15)
Z score is obtained as
a) probability a bottle will contain between 2.00 and 2.03 liters
=P(2<x<2.03) = P(-1.33<Z<2)
= 0.4082+0.4772
=0.8854
b) P(X<2) = P(Z<-1.33) =0.5-0.4082 = 0.0918
c) 2% of containers
|z|<0.11
X lies between 0.6883 and 3.352 l
Answer:
Given the consumer is 18 to 24 years old, there is 37% probability that he uses a plastic card.
Step-by-step explanation:
This can be formulated as the following problem:
What is the probability of B happening, knowing that A has happened.
It can be calculated by the following formula
Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.
In this problem, we have:
What is the probability of the consumer using a plastic card, given that the consumer is 18 to 24 years old.
The problem states that the probability that a consumer uses a plastic card when making a purchase is .37, so
P(A/B) is the probability that the consumer being 18 to 24 years old, given that he uses a plastic card. The problem states that this probability is .19. So
P(A) is the probability that the consumer is 18 to 24 years old. There is a .81 probability that the consumer is more than 24 years old. So there is a .19 probability that he is 18 to 24 years old. So
The probability is
Given the consumer is 18 to 24 years old, there is 37% probability that he uses a plastic card.