Answer:
The most abundant type of pollution in national parks at that time was air pollution and it had begun to reduce biodiversity as organisms were leaving polluted areas for cleaner ones, or they simply were not able to survive.
Answer: 4%
Out of 5000kcal, the owl loses 2300kcal which mean it could only process 2700kcal. Out of 2700kcal processed, 2500 kcal is used for cellular respiration so there is 200 kcal used to make body cells. The production efficiency would be: 200kcal/5000kcal= 4%
<u>Given:</u>
Present population of bison = 3652
Maximum growth rate = 0.28
<u>To find:</u>
The population of bison after one year.
<u>Solution:</u>
The future population can be calculated with the help of the following formula,

where
is the future population,
is the present population, r is the growth rate and n is the number of years.
On substituting the given values in the formula we get,


Therefore, the population size of bison after one year is 4675. The park does not have to control the population because the growth rate is on an average scale.
Answer:
A. 1' ... 5'
Explanation:
The pentose sugars present in nucleotides have five-carbon structures. Other components of a nucleotide are a phosphate group and a nitrogenous base. The nitrogenous base in a nucleotide can be a purine or pyrimidine. The purine bases are covalently joined to the 1' carbon atom of the pentose sugar at their N-9. The bond between the nitrogenous base and a pentose sugar is called the N-beta glycosyl bond.
Similarly, N-1 of a pyrimidine base is covalently linked to the 1' carbon of the pentose sugar. The phosphate group of a nucleotide is bonded to the 5' carbon of the pentose sugar.
A. respiratory acidosis
Blood analysis indicates a low pH, and the patient is breathing rapidly.