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pychu [463]
2 years ago
6

How would you combine reactions A–C, shown below, to obtain the overall reaction: $$ Please select all that apply.

Chemistry
1 answer:
snow_lady [41]2 years ago
4 0

Answer:

By eating a sandwich

Explanation:

your welcome nigel

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Of the elements: b, c, f, li, and na. the element with the highest ionization energy is
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Driving cars lowers the pH of the oceans by _______.
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Correct answer: a. releasing CO2 that dissolves and forms acid in the oceans

The fuels used in automobiles release gases like carbon dioxide, carbon monoxide, oxides of nitrogen and sulfur. Carbon dioxide when dissolved in water forms carbonic acid. So, when the usage of cars is high, these emissions of carbon-dioxide into the atmosphere increase and this leads to the lowering of pH of the oceans as the carbon dioxide present in higher amounts in to atmosphere diffuses into the oceanic waters and form carbonic acid which makes the ocean slightly acidic.

CO_{2}(g) + H_{2}O (l)  H_{2}CO_{3}(aq)

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Olympic cyclist fill their tires with helium to make them lighter. Calculate the mass of air in an air filled tire and the mass
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<u>Answer:</u> The mass difference between the two is 7.38 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas follows:

PV=nRT

where,

P = pressure = 125 psi = 8.50 atm    (Conversion factor:  1 atm = 14.7 psi)

V = Volume = 855 mL = 0.855 L    (Conversion factor:  1 L = 1000 mL)

T = Temperature = 25^oC=[25+273]K=298K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

8.50atm\times 0.855L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{8.50\times 0.855}{0.0821\times 298}=0.297mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For air:</u>

Moles of air = 0.297 moles

Average molar mass of air = 28.8 g/mol

Putting values in equation 1, we get:

0.297mol=\frac{\text{Mass of air}}{28.8g/mol}\\\\\text{Mass of air}=(0.297mol\times 28.8g/mol)=8.56g

Mass of air, m_1 = 8.56 g

  • <u>For helium gas:</u>

Moles of helium = 0.297 moles

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

0.297mol=\frac{\text{Mass of helium}}{4g/mol}\\\\\text{Mass of helium}=(0.297mol\times 4g/mol)=1.18g

Mass of helium, m_2 = 1.18 g

Calculating the mass difference between the two:

\Delta m=m_1-m_2

\Delta m=(8.56-1.18)g=7.38g

Hence, the mass difference between the two is 7.38 grams.

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