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SpyIntel [72]
2 years ago
3

What is the nth term rule of the quadratic sequence below? 7, 14, 23, 34, 47, 62, 79 Please could someone help me and write a st

ep by step explanation? Thanks :D
Mathematics
1 answer:
belka [17]2 years ago
5 0

Step-by-step explanation:

The first differences are 7,9,11,13,15,17 and the second differences are 2.

This means that the first term of the sequence is n^2.

Subtracting n^2 from the sequence gives 6,10,14,18,22,26, which has nth term of 4n + 2.

So putting these together gives a nth term of the quadratic sequence of n^2 + 4n + 2.

Hope it helped and tell me if I went wrong :)

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Answer:

Range = 16

Inter\ Quartile\ Range = 6.75

Variance = 20.44

Standard\ Deviation = 4.52

Step-by-step explanation:

Given

4, 17, 12, 9, 6, 10, 1, 5, 9, 3

Calculating the range;

Range = Highest - Lowest

From the given data;

Highest = 17 and Lowest = 1

Hence;

Range = 17 - 1

Range = 16

Calculating the Inter-quartile Range

Inter quartile range (IQR) is calculates as thus

IQR = Q_3 - Q_1

Where

Q3 = Upper Quartile and Q1 = Lower Quartile

<em />

<em>Start by arranging the data in ascending order</em>

1, 3, 4, 5, 6, 9, 9, 10, 12, 17

N = Number of data; N = 10

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Calculating Q3

Q_3 = \frac{3}{4}(N+1) th\ item

<em>Substitute 10 for N</em>

Q_3 = \frac{3}{4}(10+1) th\ item

Q_3 = \frac{3}{4}(11) th\ item

Q_3 = \frac{33}{4} th\ item

Q_3 = 8.25 th\ item

Express 8.25 as 8 + 0.25

Q_3 = (8 + 0.25) th\ item

Q_3 = 8th\ item + 0.25 th\ item

Express 0.25 as fraction

Q_3 = 8th\ item +\frac{1}{4} th\ item

Q_3 = 8th\ item +\frac{1}{4} (9th\ item - 8th\ item)

From the arranged data;

8th\ item = 10 and 9th\ item = 12

Q_3 = 8th\ item +\frac{1}{4} (9th\ item - 8th\ item)

Q_3 = 10 +\frac{1}{4} (12 - 10)

Q_3 = 10 +\frac{1}{4} (2)

Q_3 = 10 +0.5

Q_3 = 10.5

Calculating Q1

Q_1 = \frac{1}{4}(N+1) th\ item

<em>Substitute 10 for N</em>

Q_1 = \frac{1}{4}(10+1) th\ item

Q_1 = \frac{1}{4}(11) th\ item

Q_1 = \frac{11}{4} th\ item

Q_1 = 2.75 th\ item

Express 2.75 as 2 + 0.75

Q_1 = (2 + 0.75) th\ item

Q_1 = 2nd\ item + 0.75 th\ item

Express 0.75 as fraction

Q_1 = 2nd\ item +\frac{3}{4} th\ item

Q_1 = 2nd\ item +\frac{3}{4} (3rd\ item - 2nd\ item)

From the arranged data;

2nd\ item = 3 and 3rd\ item = 4

Q_1 = 3 +\frac{3}{4} (4 - 3)

Q_1 = 3 +\frac{3}{4} (1)

Q_1 = 3 +0.75

Q_1 = 3 .75

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Recall that

IQR = Q_3 - Q_1

IQR = 10.5 - 3.75

IQR = 6.75

Calculating Variance

Start by calculating the mean

Mean = \frac{1+3+4+5+6+9+9+10+12+17}{10}

Mean = \frac{76}{10}

Mean = 7.6

Subtract the mean from each data, then square the result

(1 - 7.6)^2 = (-6.6)^2 = 43.56

(3 - 7.6)^2 = (-4.6)^2 = 21.16

(4 - 7.6)^2 = (-3.6)^2 = 12.96

(5 - 7.6)^2 = (-2.6)^2 = 6.76

(6 - 7.6)^2 = (-1.6)^2 = 2.56

(9 - 7.6)^2 = (1.4)^2 = 1.96

(9 - 7.6)^2 = (1.4)^2 = 1.96

(10 - 7.6)^2 = (2.4)^2 = 5.76

(12 - 7.6)^2 = (4.4)^2 = 19.36

(17 - 7.6)^2 = (9.4)^2 = 88.36

Sum the result

43.56 + 21.16 + 12.96 + 6.76 + 2.56 + 1.96 + 1.96 + 5.76 + 19.36 + 88.36 = 204.4

Divide by number of observation;

Variance = \frac{204.4}{10}

Variance = 20.44

Calculating Standard Deviation (SD)

SD = \sqrt{Variance}

SD = \sqrt{20.44}

SD = 4.52 <em>(Approximated)</em>

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