Question

Recipe ingredients remain in a constant ratio no matter how many servings are prepared. Which table shows a possible

Answer 1

Answer:

Table N 4

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

Verify the table 4

For x=1, y=2

so

y/x=2/1=2

For x=2, y=4

so

y/x=4/2=2

For x=3, y=6

so

y/x=6/3=2

therefore

The constant of proportionality k is equal to 2 and the equation is equal to

y=2x

The table 4 represent a direct variation, therefore is a possible ratio table for ingredients X and Y

Answer 2

Answer:

The correct option is 4.

Step-by-step explanation:

It given that recipe ingredients remain in a constant ratio no matter how many servings are prepared.

It means the relation between x and y is

$y\propto x$

$y=kx$

where k is constant of proportionality.

We need to find a possible ratio table for ingredients X and Y for the given number of servings.

In table 1,

$\frac{y_1}{x_1}=\frac{2}{1}$

$\frac{y_2}{x_2}=\frac{3}{2}$

$\frac{y_1}{x_1}\neq \frac{y_2}{x_2}$

Option 1 is incorrect.

In table 2,

$\frac{y_1}{x_1}=\frac{2}{1}=2$

$\frac{y_2}{x_2}=\frac{4}{2}=2$

$\frac{y_3}{x_3}=\frac{8}{3}$

$\frac{y_1}{x_1}\neq \frac{y_3}{x_3}$

Option 2 is incorrect.

In table 3,

$\frac{y_1}{x_1}=\frac{2}{1}$

$\frac{y_2}{x_2}=\frac{3}{2}$

$\frac{y_1}{x_1}\neq \frac{y_2}{x_2}$

Option 3 is incorrect.

In table 4,

$\frac{y_1}{x_1}=\frac{2}{1}=2$

$\frac{y_2}{x_2}=\frac{4}{2}=2$

$\frac{y_3}{x_3}=\frac{6}{3}=2$

$\frac{y_}{x_1}=\frac{y_2}{x_2}=\frac{y_3}{x_3}$

Option 4 shows a possible  ratio table for ingredients X and Y for the given number of servings.

Therefore the correct option is 4.