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Firdavs [7]
2 years ago
10

What mass of nickel (Ni) is in a 2.4 Kg sample of propanol if the concentration is 20 ppb ? (atomic mass of Ni = 58.69)

Chemistry
1 answer:
asambeis [7]2 years ago
8 0

Answer:

The mass of nickel is 48μg

Explanation:

Parts per billion is a way to describe small concentrations and is defined as the ratio between μg of solute and kg of solvent.

If a solution of nickel in propanol is 20ppb, contains 20μg of nickel in 1 kg of propanol.

Thus, a sample of 2.4kg of propanol will contain:

2.4kg × (20μg nickel / 1kg) = 48μg nickel

<h3>The mass of nickel is 48μg</h3>
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Plseas help Calculate the amount of moles in 57.6 Liters of Carbon Dioxide.
slavikrds [6]
Convert 57.6 L to dm3 and divide it by 24
8 0
2 years ago
According to the following reaction, what volume of 0.244 M KCl solution is required to react exactly with 50.0 mL of 0.210 M Pb
svetoff [14.1K]

Answer:

86 mL

Explanation:

First find the moles of Pb (NO3)2

n=cv

where

c ( concentration)= 0.210 M

v ( volume in L) =0.05

n= 0.210 × 0.05

n= 0.0105

Using the mole ratio, we can find the moles of KCl by multiplying by 2

n (KCl) =0.0105 ×2

=0.021

v (KCl)= n/ c

= 0.021/ 0.244

=0.08606557377

=0.086 L

= 86 mL

8 0
2 years ago
Read 2 more answers
Which statement explains why NaBr is classified as a compound?
charle [14.2K]

Answer:1

Explanation:i know cuz I got it right

5 0
2 years ago
A sample of vinegar was found to have an acetic acid concentration of 0.8846 m. What is the acetic acid % by mass? Assume the de
jenyasd209 [6]

Answer:

5.3%

Explanation:

Let the volume be 1 L

volume , V = 1 L

use:

number of mol,

n = Molarity * Volume

= 0.8846*1

= 0.8846 mol

Molar mass of CH3COOH,

MM = 2*MM(C) + 4*MM(H) + 2*MM(O)

= 2*12.01 + 4*1.008 + 2*16.0

= 60.052 g/mol

use:

mass of CH3COOH,

m = number of mol * molar mass

= 0.8846 mol * 60.05 g/mol

= 53.12 g

volume of solution = 1 L = 1000 mL

density of solution = 1.00 g/mL

Use:

mass of solution = density * volume

= 1.00 g/mL * 1000 mL

= 1000 g

Now use:

mass % of acetic acid = mass of acetic acid * 100 / mass of solution

= 53.12 * 100 / 1000

= 5.312 %

≅ 5.3%

3 0
2 years ago
A gram of gasoline produces 45.0kJ of energy when burned. Gasoline has a density of 0.77/gmL. How would you calculate the amount
Ber [7]

Answer:

Math expression: =\frac{0.77\ g/ml*5200\ ml}{1\ g} *45.0\ kJ

Explanation:

<u>Given:</u>

Energy produced per gram of gasoline = 45.0 kJ

Density of gasoline = 0.77 g/ml

Volume of gasoline = 5.2  L=5200 ml

<u>To determine:</u>

The amount of energy produced by burning 5.2 L gasoline

<u>Calculation set-up:</u>

1. Calculate the mass (m) of gasoline given the density (d) and volume (v)

m = d*v\\\\m = 0.77 g/ml*5200 ml

2. Calculate the amount of energy produced

=\frac{0.77\ g/ml*5200\ ml}{1\ g} *45.0\ kJ=180180 kJ

7 0
2 years ago
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