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finlep [7]
2 years ago
14

Find the value of x in each case:

Mathematics
1 answer:
timurjin [86]2 years ago
7 0

Answer:

angle FGE = 36

angle GEL = 72

and angle GFH = 144

Step-by-step explanation:

well you know that angle GEF = 180 -2x

and that angle GFE = 180 -4x

so all the angles in triangle GEF must add to 180

so you have 180 = 180 -2x + 180 -4x + x

180 = 360 -5x

5x = 180

x = 36

so angle FGE = 36

angle GEL = 72

and angle GFH = 144

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Consider the midterm and final for a statistics class. Suppose 13% of students earned an A on the midterm. Of those students who
padilas [110]

Answer:

There is a 38.97% probability that this student earned an A on the midterm.

Step-by-step explanation:

The first step is that we have to find the percentage of students who got an A on the final exam.

Suppose 13% students earned an A on the midterm. Of those students who earned an A on the midterm, 47% received an A on the final, and 11% of the students who earned lower than an A on the midterm received an A on the final.

This means that

Of the 13% of students who earned an A on the midterm, 47% received an A on the final. Also, of the 87% who did not earn an A on the midterm, 11% received an A on the final.

So, the percentage of students who got an A on the final exam is

P_{A} = 0.13(0.47) + 0.87(0.11) = 0.1568

To find the probability that this student earned an A on the final test also earned on the midterm, we divide the percentage of students who got an A on both tests by the percentage of students who got an A on the final test.

The percentage of students who got an A on both tests is:

P_{AA} = 0.13(0.47) = 0.0611

The probability that the student also earned an A on the midterm is

P = \frac{P_{AA}}{P_{A}} = \frac{0.0611}{0.1568} = 0.3897

There is a 38.97% probability that this student earned an A on the midterm.

5 0
2 years ago
Tan 235° = 2tan20°+ tan215°​
Mariulka [41]

Given :  tan 235 = 2 tan 20 + tan 215

To Find : prove that

Solution:

tan 235 = 2 tan 20 + tan 215

Tan x = Tan (180 + x)

tan 235 = tan ( 180 + 55) = tan55

tan 215 = tan (180 + 35) = tan 35

=> tan 55 = 2tan 20 + tan 35

55 = 20 + 35

=> 20  = 55 - 35

taking Tan both sides

=> Tan 20 = Tan ( 55 - 35)

=> Tan 20  = (Tan55 - Tan35) /(1 + Tan55 . Tan35)

Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1

=> Tan 20  = (Tan 55 - Tan 35) /(1 + 1)

=> Tan 20  = (Tan 55 - Tan 35) /2

=> 2 Tan 20  = Tan 55 - Tan 35

=> 2 Tan 20 +  Tan 35 = Tan 55

=>  tan 55 = 2tan 20 + tan 35

=>  tan 235 = 2tan 20 + tan 215

QED

Hence Proved

5 0
1 year ago
Roosevelt High School is known for their marching band's attention to detail. Each band member makes sure that every step is exa
almond37 [142]
Each member takes 40 yards marches finish
4 0
2 years ago
Danny Henry made a waffle on his six-inch-diameter circular griddle using batter containing a half a cup of flour. Using the sam
Mekhanik [1.2K]

Answer:

He'll need 288 cups to make a waffle on his 24 foot diameter circular griddle.

Step-by-step explanation:

In order to find out how much batter Danny needs we first need to compute the area of the first pans, since it is a circular pan their area is given by A = 2*pi*r. So we have:

Area of the first pan = 2*pi*(6/2) = 18.84 square inches

Area of the second pan = 2*pi*(24/2) = 75.36 square foots

We now need to convert these values to be in the same unit, we'll convert from square foots to square inches:

Area of the second pan = 75.36 * (12)^2 = 10851.84 square inches

We can now use a proportion knowing that the batter and the thickness of the waffles are the same. If 0.5 cup of flour can make a waffle on 18.84 square inches then x cup of flour can make a waffle on 10851.85 square inches. Writing this in a mathematical form, we have:

0.5/x = 18.84/10851.84

18.84x = 0.5*10851.85

x = 10851.85*0.5/18.84 =288 cups

7 0
2 years ago
Two wires with lengths of 448 cm and 616 cm are to be cut into pieces of all the same length without a remainder. Find the great
Y_Kistochka [10]

Answer:

56 cm

Step-by-step explanation:

We need ro find the GCD of these numbers. In finding the GCD, we list the multiples of the number, beginning with the smallest number. Here, the

The factors of 616=2*2*2*7*11

The factors of 448 =2*2*2*2*2*2*7

Common factors in both are 2*2*2*7=56

Therefore, the greatest possible length is 56 cm

6 0
2 years ago
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