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ohaa [14]
2 years ago
9

Phil’s filling station gas station operates on a patch on the highway in a patch where there were no gas stations close by. It e

njoyed high profits. After a while, Glen’s gas another gas station opened up close by. The profits for the first gas station are likely to decrease because a. ​it has to lower prices, since its product is now more price elastic b. ​It has to lower prices since its product is now more price inelastic c. ​due to the increased availability of substitutes d. ​both A&C
Business
1 answer:
Harman [31]2 years ago
7 0

Answer: Both A and C

Explanation:

The Phil's filling gas station operates on a highway was solo in that area and had no other gas stations nearby.It enjoyed the profit .

Sooner a new gas station opened near Phil's gas station.The profit of the Phil's gas station started decreasing. This was because the it has to lower prices to increase its demand and as there were substitutes available in the market now, people moved to another gas stations for their need.

Both of the cases will decrease its profit.

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Paris operates a talent agency as a sole proprietorship, and this year she incurred the following expenses in operating her tale
Marrrta [24]

Answer:

The total deductible amount of these expenditures is $450.

Explanation:

Half of any cost of meals and entertainment to which business discussion is associated and appropriate records kept is allowed to be deducted.

Since it is only tickets to the opera with a client following a business meeting that meet this condition, 50% of the total amount of $900 which is $450 is deductible.

3 0
2 years ago
Micromedia offers computer training seminars on variety of topics. In the seminars each student works at a personal computer, pr
Fiesta28 [93]

Answer:

Explanation:

a. Total cost=4800+30*2*x=4800+60x

The cost for the conference room, instructor compensation, lab assistants, and promotion is $4800

Computer rental - $30 per day

Length of seminar - 2 days

X - number of  students

b. total profit = revenue-costs incurred = 300x-(4800+60x)=240x-4800

Projected fee - $300 per student

c. If 30 students enrolled

profit=240*30-4800=7200-4800=2400

d. 240x-4800=0

x=4800/240=20

break-even point is 20, it is point at with profit will equal zero

5 0
1 year ago
The Benson Bearing Company sells Textron, Inc. a quantity of baseball bats that were stored in an independent warehouse at the t
polet [3.4K]

Answer:

at the time it receives a negotiable warehouse receipt for the bats.

Explanation:

Benson Bearing Company is selling bats to Textron inc. The bats are stored at an independent warehouse not controlled by Benson Company.

Of the contract states that Textron will pick up the bats at the warehouse, the risk of loss passes to Textron when it recieved a negotiable warehouse reciept for the bats.

This is because the warehouse is not controlled by Benson Company and issuing a warehouse reciept is equivalent to delivering the goods to Textron.

7 0
2 years ago
With respect to delaying revenue recognition until completion of a long-term contract, it is the case that: Multiple Choice A) E
hichkok12 [17]
<h2>Estimated losses on the overall contract are recognized before the contract is completed. </h2>

Explanation:

Revenue recognition cannot be done prior to the completion of contract.

But the asset can be created. Only after the contract gets completed the revenue recognition can be realized.

For a long-term project, the revenue can be recognized based on the percentage of completion.

Revenue recognition keeps financial transactions aligned.

Option A: valid

Option B Invalid, because expenses are also recognized

Option C: This process is acceptable.

Option D: Gains and profits are calculated in this type of method

8 0
2 years ago
Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

4 0
2 years ago
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