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vodomira [7]
2 years ago
15

Every noticeable event, transaction, interaction, request and reply, and so on are being expectantly captured and saved in stora

ge appliances and arrays for real-time as well as posterior investigations create something we call it ______________.
Computers and Technology
1 answer:
Debora [2.8K]2 years ago
7 0

Answer:

Every noticeable event, transaction, interaction, request and reply, and so on are being expectantly captured and saved in storage appliances and arrays for real-time as well as posterior investigations create something we call it <u>Big Data.</u>

<u></u>

Another way to look at is that it comprises massive amounts of data that keeps on growing exponentially over time so much so that it cannot be processed or analyzed using usual data processing techniques.

Cheers!

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Which of the following statements is true? A. Interpreted programs run faster than compiled programs. B. Compilers translate hig
alina1380 [7]

Answer:

B.

Explanation:

Computer programs are written in high level languages. Every language has its own set of syntax and semantics.

Computer only understands instructions in machine language which is written using strings of 0 and 1.

Thus, for execution of a high level language program, it is mandatory to convert high level instructions into machine instructions.

This translation into machine language is done in two ways – compilation or interpretation.

Some languages are compiled while others are interpreted.

Both compilers and interpreters are programs and process the high level language program as needed.

Compiler

Any program written in high level language is compiled.

The program is first analyzed before compilation. This process takes time. The analysis phase is called pre processing.

The program compilation stops only when the program is completely analyzed. Hence, it is difficult to locate the error in the program. This makes debugging easy.

Debugging is defined as removal of errors in the programs.

A compiler is responsible for converting high level language code into machine level code.

The complete program undergoes compilation at the same time.

A compiled program executes faster than an interpreted program.

A compiled program produce machine code which is a collection of 0 and 1, hence, it takes less time to execute.

Examples of compiled languages are C and C++.

Interpreter

Some high level languages are interpreted.

The high level language code is translated into an intermediate level code. This intermediate code is then executed.

The analysis of the program takes less time and takes place before interpretation begins. The analysis phase is called pre processing.

An interpreted program is translated one line at a time.

The program interpretation stops when an error is encountered. This makes debugging easy.

Debugging is defined as removal of errors in the programs.

Examples of interpreted languages include Python and Ruby.

6 0
2 years ago
Read 2 more answers
#Write a function called is_composite. is_composite should #take as input one integer. It should return True if the #integer is
malfutka [58]

Answer:

// A optimized school method based C++ program to check  

// if a number is composite.  

#include <bits/stdc++.h>  

using namespace std;  

bool isComposite(int n)  

{  

// Corner cases  

if (n <= 1) return false;  

if (n <= 3) return false;  

// This is checked so that we can skip  

// middle five numbers in below loop  

if (n%2 == 0 || n%3 == 0) return true;  

for (int i=5; i*i<=n; i=i+6)  

 if (n%i == 0 || n%(i+2) == 0)  

 return true;  

return false;  

}  

// Driver Program to test above function  

int main()  

{  

isComposite(11)? cout << " true\n": cout << " false\n";  

isComposite(15)? cout << " true\n": cout << " false\n";  

return 0;  

}

Explanation:

3 0
2 years ago
Write a static generic method PairUtil.minmax that computes the minimum and maximum elements of an array of type T and returns a
Gnesinka [82]

Answer:

Explanation:

The following code is written in Java. It is hard to fully create the code without the rest of the needed code including the T class and the Measurable interface. Regardless the following code can be implemented if you have that code available.

 public static T minmax(ArrayList<T> mylist) {

       T min = new T();

       T max = new T();

       for (int x = 0; x < mylist.size(); x++) {

           if (mylist.get(x) > max) {

               max = mylist.get(x);

           } else if (mylist.get(x) < min) {

               min = mylist.get(x);

           }

       }

       

       return (min, max);

   }

5 0
2 years ago
___refers to self-acting or self-operating.
lisabon 2012 [21]

Answer:

do it to me watch this

Explanation:

trailing zeros in a whole number with no decimal shown are NOT significan

6 0
2 years ago
Give a proof for each statement.
Marrrta [24]

Answer:

  • If a group of 9 kids have won a total of 100 trophies, then at least one of the 9 kids has won at least 12 trophies.
  • If a person buys at least 400 cups of coffee in a year, then there is at least one day in which the person has bought at least two cups of coffee.
  • The average of three real numbers is greater than or equal to at least one of the numbers.

Explanation:

1)

Suppose that  each kid has less than 12 trophies

Total trophies = 100

Maximum trophies won by one kid = 11

total kids = 9

total number of trophies = 9 * 11 = 99 which contradicts the fact the total number of trophies are 100

2)

Suppose that  person has less than 2 cups of coffee a day

Total cups of coffee = 400

he has bought at least one cup of coffee each day

which means

total number of cups of coffee = 1* 366 = 366 which contradicts the fact the person buys at least 400 cups of coffee in a year

3)

Average of three number = (a+ b+ c)/3

suppose that there are real numbers a, b, and c such  that all three numbers are less than the average of the three numbers.

Let m be the average (a+b+c )/3 = m. Then our assumption states that (a < m) and  (b < m) and (c < m). By adding all the inequalities we get a + b + c < 3m. But m is  defined to be (a+b+c) /3  , so a + b + c = 3m.  But now we have that 3m = a + b + c < 3m. So 3m < 3m which is an obvious  contradiction. Thus our claim is true

7 0
2 years ago
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