All categories

2 years ago

Round 21,253 to the nearest hundred.

Mathematics

1 answer:

Mazyrski [523]2 years ago

6 0

Answer:

Hey there! The answer to your question is 21,300

Step-by-step explanation:

If we look at the 253 it is most close to 300 not 200 so the answer will be 21,300

Hope that helps!

By: xBrainly

You might be interested in

A department store chain is expanding into a new market and is considering 22 different sites on which to locate 6 stores.

NARA [144]

Answer:

74613

Step-by-step explanation:

22C6 = 74613

3 0

2 years ago

Which expressions are equivalent to (5g+3h+4)\cdot2(5g+3h+4)⋅2left parenthesis, 5, g, plus, 3, h, plus, 4, right parenthesis, do

Semenov [28]

Answer:

C None of the above

Step-by-step explanation:

The expression

(5g+3h+4)⋅2

can be expanded using distributive property as follows:

5g⋅2 + 3h⋅2 + 4⋅2 =

= 10g + 6h + 8

option A expression

(5g+3h)⋅8

can be expanded using distributive property as follows:

5g⋅8+3h⋅8 =

= 40g + 24h

which is different from 10g + 6h + 8

Option B expression

(5g+3h)⋅6

can be expanded using distributive property as follows:

5g⋅6+3h⋅6 =

= 30g + 18h

which is different from 10g + 6h + 8

6 0

1 year ago

Read 2 more answers

Each year a town holds a winter carnival this year 40% of the attendees were children under the age of 10 if 304 children under

tatuchka [14]

Answer:

760 attendees

Step-by-step explanation:

40% of the attendees is 304. That means you can add 304 to 304 (304 x 2) to get 608. To get the last 20%, divide 304 by 2, because 40(%) divided by 2 is 20(%). The answer to that is 152. Now, add it all up. 608 + 152 = 760.

In conclusion, there were 760 attendees at the carnival.

4 0

2 years ago

You need to fill a football with air to play with it. You know that your pump expels air at speed of 8.2 ft/s. The needle of you

abruzzese [7]

Jjjjjjjjhjjjjhhhhjhhjjjjjhhhhhhh

8 0

2 years ago

Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa

Alik [6]

Answer:

We conclude that the proportion of student body in favor of him is significantly less than or equal to 50%.

Step-by-step explanation:

We are given that Mike runs for the president of the student government and is interested to know whether the proportion of the student body in favor of him is significantly more than 50 percent.

A random sample of 100 students was taken. Fifty-five of them favored Mike.

Let p = proportion of the students who are in favor of Mike.

So, Null Hypothesis, $H_0$ : p $\leq$ 50% {means that the proportion of student body in favor of him is significantly less than or equal to 50%}

Alternate Hypothesis, $H_A$ : p > 50% {means that the proportion of student body in favor of him is significantly more than 50%}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students body in favor of Mike = $\frac{55}{100}$ = 0.55

n = sample of students taken = 100

So, test statistics = $\frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }$

= 1.01

The value of z test statistics is 1.01.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is less than the critical value of z as 1.01 < 1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the proportion of student body in favor of him is significantly less than or equal to 50% or proportion of the students in favor of Mike is not significantly greater than 50 percent.

4 0

1 year ago