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Norma-Jean [14]
2 years ago
9

Sabrina is making an open box

Mathematics
1 answer:
Ad libitum [116K]2 years ago
4 0

Answer:

yay! sabrina is making an open box

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Use a negative factor to factor the expression -5g + 15h - 25
Firdavs [7]

Answer:

<h2>-5g + 15h - 25 = -5 × (g - h + 5)</h2>

Step-by-step explanation:

-5g = -5 × g

15h = 5 × 3h

-25 = -5 × 5

-5g + 15h - 25 =  -5 × g - (-5 × 3h) + (-5 × 5) = -5 × (g - h + 5)

3 0
2 years ago
A Car is moving on a straight road with velocity 30m/s and is speeding up at constant rate and reaches a velocity of 90m/s. What
poizon [28]

Answer:

60m/s

Step-by-step explanation:

velocity of the while moving is 30 m/s and it becomes 90 m/s after speeding up at constant rate. so the average velocity of the journey is

[90+30] /2

=60 m/s

4 0
2 years ago
Here is a circle touching a square. The area of the square is 36cm squared. Work out the area of the circle. Give your answer in
Lena [83]

Answer:

see below

Step-by-step explanation:

Because the area of the square is 36 its side is 6 meaning the circle has a diameter of 6. This means that its radius is 3 so its area is 3² * π = 9π.

8 0
2 years ago
during the summer winnie delivers flowers and bob babysits for neighbors to show their earnings winnie makes a table which state
miv72 [106K]
  1. Winnie earns $12.30 and Bob earns $24.30.
  2. Bob earns $8.10 and earns$4.10
  3. Winnie earns$12.15 and Bob earns $6.15
  4. Winnie earns $4.05 and Bob earns $2.05

7 0
2 years ago
Read 2 more answers
If events X and Y are independent, what must be true? Check all that apply. P(Y | X) = 0 P(X | Y) = 0 P(Y | X) = P(Y) P(Y | X) =
lana [24]

if events X and Y are independent, then for intersection we multiply the probability

P(Y∩X)  = P(Y) * P(X)

We know that

P(Y|X) =\frac{P(YintersectionX)}{P(X)}

Now we replace P(Y) * P(X) for  P(Y∩X)

P(Y|X) =\frac{P(Y)*P(X)}{P(X)}

Cancel out P(X)

So P(Y|X) = P(Y)

Like that

P(X|Y) =\frac{P(XintersectionY)}{P(Y)}

Now we replace P(X) * P(Y) for  P(X∩Y)

P(X|Y) =\frac{P(X)*P(Y)}{P(Y)}

Cancel out P(Y)

So P(X|Y) = P(X)

P(Y | X) = P(Y)  and P(X | Y) = P(X)  are true



3 0
2 years ago
Read 2 more answers
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