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Dmitry [639]
1 year ago
9

Jerome was curious if \triangle ABC△ABCtriangle, A, B, C was congruent to \triangle FED△FEDtriangle, F, E, D, so he tried to map

one triangle onto the other using transformations: Jerome concluded: "It's not possible to map \triangle ABC△ABCtriangle, A, B, C onto \triangle FED△FEDtriangle, F, E, D using a sequence of rigid transformations, so the triangles are not congruent." What error did Jerome make in his conclusion?\
Mathematics
1 answer:
Lunna [17]1 year ago
8 0

Answer: C

Step-by-step explanation: I just did it on Khan Academy.

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50 degrees is the answer
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Fruit juice comes in two types of containers. The first is a rectangular prism that is 9 inches tall and has a rectangular base
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The volume of a rectangular prism:

V_p=Bh\\\\B=wl\\\\w=2\ in;\ l=3\ in;\ h=9\ in

substitute

V_p=2\cdot3\cdot9=54\ in^3

The volume of a cylinder:

V_c=\pi r^2h\\\\r=1.5\ in;\ h=8\ in

substitute:

V_c=\pi\cdot(1.5)^2\cdot8=\pi\cdot2.25\cdot8=18\pi\ in^3\approx18\cdot3.14=56.52\ in^3

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Please help!! I need to get this done! Im begging you, brainliest and points!
Viefleur [7K]

Answer:

<em>Solution; ( 1, 0 ), and ( - 3, 4 )</em>

Step-by-step explanation:

See procedure below;

First let us make these two functions ( y = -x + 1 , y = x^2 + x - 2 ) equivalent;

- x + 1  = x^2 + x - 2,

-x - x + 1 + 2 - x^2 = 0,

- 2x + 3 - x^2 = 0,

x^2 + 2x - 3 = 0,

Now factor the simplified equation;

x^2 + 2x - 3 = 0,

( x^2 - x ) + ( 3x - 3 ) = 0,

x ( x - 1 ) + 3 ( x - 1 ) = 0,

( x - 1 )( x + 3 ) = 0,

And solve for x;

x - 1 = 0, and x + 3 = 0,

x = 1, and x = - 3

Now substitute this value of x into the two functions as to receive the y  values for each x - value;

y = - ( 1 ) + 1, <em>y = 0 for x = 1</em>,

y = ( - 3 )^2 - 3 - 2, y = 9 - 3 - 2, <em>y = 4 for x = - 3</em>,

<em>Solution; ( 1, 0 ), and ( - 3, 4 )</em>

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1 year ago
A rainwater collection system uses a cylindrical storage tank with a diameter of
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Answer:

157079.6

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The percent defective for parts produced by a manufacturing process is targeted at 4%. The process is monitored daily by taking
Anna [14]

Answer:

The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

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For this problem, we have that:

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The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)

6 0
1 year ago
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