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Kamila [148]
2 years ago
11

Today, the Great Pyramid at Giza near Cairo, Egypt stands 137 meters tall, coming to a point.Its base is a square with each side

measuring 230 meters wide. What is the slope of the pyramid?

Mathematics
1 answer:
Vlad1618 [11]2 years ago
8 0
Hope you can see the picture and understand the drawings.

It can seem complex at first but you just have to think it through. 

I use pythagoras' theorem to find the diagonal of the base square and then use that information along with the height with the aid of that ever so handy pythagoras' theorem to find the length of the slope. 

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The product of sin 30 degrees and sin 60 degrees is the same as the product of
zysi [14]

Answer:

sin(30\°)*sin(60\°)=cos(60\°)*cos(30\°)

Step-by-step explanation:

we know that

sin(\alpha)=cos(\beta)

when

\alpha+\beta=90\° -------> complementary angles

so

sin(30\°)=cos(60\°)

sin(60\°)=cos(30\°)

Because

30\°+60\°=90\° -------> complementary angles

In this problem the product of

sin(30\°)*sin(60\°)

is equal to

cos(60\°)*cos(30\°)

therefore

sin(30\°)*sin(60\°)=cos(60\°)*cos(30\°)

3 0
2 years ago
Read 2 more answers
URGENT!! Please help Find the values of y=c(x) 3 square x, for x = 0, 0.008, 0.027, 0.064, 0.125, 0.216, 0.343, 0.512, , 0.729 a
mojhsa [17]

Answer:

We have

$y=c(x)=\sqrt[3]{x} $

\text{for } x = 0, 0.008, 0.027, 0.064, 0.125, 0.216, 0.343, 0.512, 0.729 \text{ and } 1

We have 10 points to find:

\text{Point A}(0, 0)

\text{Point B}(0.008, 0.2)

\text{Point C}(0.027, 0.3)

\text{Point D}(0.064, 0.4)

\text{Point E}(0.125, 0.5)

\text{Point F}(0.216, 0.6)

\text{Point G}(0.343, 0.7)

\text{Point H}(0.512, 0.8)

\text{Point I}(0.729, 0.9)

\text{Point J}(1, 1)

4 0
2 years ago
What is the least number of inequalities needed to produce a closed region?
Simora [160]
25 is the answer..............
4 0
2 years ago
A worker has a base pay of $20 per hour, gets $3 more per hour after 8 hours, and gets $4 more
GalinKa [24]

Answer:

177 $

Step-by-step explanation:

20 x8 = 160

3x3= 9

4x2=8

8+9+160= 177

6 0
2 years ago
How many ounces of pure nickel must be added to 150 ounces of alloy 70% pure to make an alloy which is 85% pure?
galben [10]

Answer:

150 oz.

Step-by-step explanation:

There are already 150 ounces of alloy of nickel.

Of this 150 oz, 70% is pure i.e. nickel content = 150(0.7) = 105 oz

Now available is

Nickel       Other metals

105                  45

Let x oz of pure nickel is added.

Then new alloy will have 105+x oz nickel in total of 150+x oz.

Percentage pure = \frac{105+x}{150+x} =85%

Simplify to get

\frac{105+x}{150+x} =\frac{85}{100} \\\\Cross multiply:\\85(150+x) =100(105+x)\\12750+85x =10500+100x\\100x-85x = 12750-10500\\15x = 2250\\x = 150

Hence answer is 150 oz should be added.

6 0
2 years ago
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