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Korvikt [17]
2 years ago
6

A card player selects a playing card from a well-shuffled deck of standard playing cards and sees if the card is a red card or n

ot. He keeps the card, and then makes another selection and sees if the card is a red card or not. He continues this process 10 times and counts the total number of red cards that he selects. Is this a binomial random variable? A. no since the total number of red cards in the deck is unknown at the start of the experiment B. no, since probabilities of drawing red cards do not remain the same from trial to trial C. yes since red cards are successes and he is counting the number of red cards drawn D. yes since a red card is a success and every other card is a failure
Mathematics
1 answer:
dmitriy555 [2]2 years ago
8 0

Answer:

A

Step-by-step explanation:

there could be no red cards inside

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Answer:

n>8

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2n +10 -10 > 26 - 10

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2n divided by 2 to leave n by itself > 16 divided by 2 ( what you do to one side is mirrored on the other side)

Therefore, n<8

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Answer:

The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

Step-by-step explanation:

We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line  x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

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He earned $114 in interest and the final amount in the account is $874

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2 years ago
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