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2 years ago

A sporting goods company is planning to manufacture a commemorative lacrosse

Mathematics

1 answer:

LiRa [457]2 years ago

5 0

Answer:

Volume of this cylinder = 785.71 Cm³

Surface area of this cylinder = 157.14 Cm²

Step-by-step explanation:

Given:

Height of cylinder = 10 Cm

Radius of cylinder = 10 / 2 = 5 Cm

Find:

Volume of this cylinder.

Surface area of this cylinder

Computation:

Volume of this cylinder = πr²h

Volume of this cylinder = (22/7)(5)²(10)

Volume of this cylinder = 785.71 Cm³

Surface area of this cylinder = 2πr(h+r)

Surface area of this cylinder = 2(22/7)(5)(10+5)

Surface area of this cylinder = 2(22/7)(5)(15)

Surface area of this cylinder = 157.14 Cm²

You might be interested in

A good indicator of the value of a company is the ratio of the price of its stock to its yearly earnings expressed as dividends.

gulaghasi [49]

Answer:

4.92 cents

Step-by-step explanation:

The Price to Earnings or P/E is the ratio of the price of its stock to its yearly earnings expressed as dividends.

The price of a stock is $36 and it's earnings are $3.00

This means the price to earnings ratio,

P/E = 36/3 = 6

Let us express this ratio as percentage. This becomes

36/3 ×100 = 1200%

This means the ratio of price to earnings = 1200%

For an increase of 20%, the ratio of price to earnings will be = 1200 + 20 = 1220%.

Let x be the the value of earnings that would increase the ratio by 20%

36/3 × 100 = 1200%

36/x × 100 = 1220℅

3600/x = 1220

x = 3600/1220 = $2.9508

The amount by which the earnings must decrease in order that the P/E ratio increases by 20% will be

$3 - $2.9508 = $0.0492.

Converting to cents, we multiply by 100. It becomes

0.0492×100 = 4.92 cents

3 0

2 years ago

Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and the e

Komok [63]

Answer:

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

Step-by-step explanation:

Independent events:

If two events, A and B, are independent, then:

$P(A \cap B) = P(A)*P(B)$

Conditional probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: At least one tag is lost

Event B: Exactly one tag is lost.

Each tag has a 40% = 0.4 probability of being lost.

Probability of at least one tag is lost:

Either no tags are lost, or at least one is. The sum of the probabilities of these events is 1. Then

$p + P(A) = 1$

p is the probability none are lost. Each one has a 60% = 0.6 probability of not being lost, and they are independent. So

p = 0.6*0.6 = 0.36

Then

$P(A) = 1 - p = 1 - 0.36 = 0.64$

Intersection:

The intersection between at least one lost(A) and exactly one lost(B) is exactly one lost.

Then

Probability at least one lost:

First lost(0.4 probability) and second not lost(0.6 probability)

First not lost(0.6 probability) and second lost(0.4 probability)

$P(A \cap B) = 0.4*0.6 + 0.6*0.4 = 0.48$

Find the probability that exactly one tag is lost, given that at least one tag is lost (write it up to second decimal place).

$P(B|A) = \frac{0.48}{0.64} = 0.75$

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

8 0

2 years ago

What is the length of line segment EF if DE is 6ft and DF is 11ft and angle FDE is 40 degrees

Anna [14]

Answer:

The length of EF = 7.48 feet

Step-by-step explanation:

* Lets consider these tree segment formed triangle DEF

- We have the length of two sides and the measure of the

including angle between these two sides

* So we can use the cos Rule to find the length of the third side

- The cos rule ⇒ a² = b² + c² - 2bc cosA

# a is the side opposite to angle A

# b is the side opposite to angle B

# c is the side opposite to angle C

# Angle A is the including angle between b and c

* In the problem

∵ DE = 6 feet

∵ DF = 11 feet

∵ m∠FDE = 40° ⇒ including angle between DE and DF

and opposite to EF

- By using cos Rule

∴ (EF)² = (DE)² + (DF)² - 2(DE)(DF) cos∠FDE

∴ (EF)² = (6)² + (11)² - 2(6)(11) cos(40)

∴ (EF)² = 55.882133 ⇒ take square root for both sides

∴ EF = 7.47543 ≅ 7.48 feet

* The length of EF = 7.48 feet

6 0

2 years ago

A fishing boat lies 200 m due south of a large tree on the shoreline and 300 m southwest of the dock. The shoreline runs East to

Lunna [17]

Tree...........................dock
.
.
.
.
.
boat

use Pythagorean Theorem to satisfy...a^2 + b^2 = c^2

200^2 + b^2 = 300^2
b^2 = 300^2 - 200^2
b^2 = 50000 (get square root of each)
b = 223.606 (rounded to the nearest tenth.... = 223.6

4 0

2 years ago

Read 2 more answers

Which are the solutions of x2 = –11x + 4? StartFraction negative 11 minus StartRoot 137 EndRoot Over 2 EndFraction comma StartFr

Marysya12 [62]

Answer:

$x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}$

Step-by-step explanation:

Given the following quadratic equation:

$x^2 = -11x + 4$

The steps to solve it are:

1. Move the terms to one side of the equation:

$x^2+11x- 4=0$

2. Apply the Quadratic formula $x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$ .

In this case we can identify that:

$a=1\\b=11\\c=-4$

Then, substituting these values into the Quadratic formula we get the following solutions:

$x=\frac{-11\±\sqrt{11^2-4(1)(-4)} }{2(1)}$

$x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}$

3 0

2 years ago

Read 2 more answers