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2 years ago

A sporting goods company is planning to manufacture a commemorative lacrosse

Mathematics

1 answer:

LiRa [457]2 years ago

5 0

Answer:

Volume of this cylinder = 785.71 Cm³

Surface area of this cylinder = 157.14 Cm²

Step-by-step explanation:

Given:

Height of cylinder = 10 Cm

Radius of cylinder = 10 / 2 = 5 Cm

Find:

Volume of this cylinder.

Surface area of this cylinder

Computation:

Volume of this cylinder = πr²h

Volume of this cylinder = (22/7)(5)²(10)

Volume of this cylinder = 785.71 Cm³

Surface area of this cylinder = 2πr(h+r)

Surface area of this cylinder = 2(22/7)(5)(10+5)

Surface area of this cylinder = 2(22/7)(5)(15)

Surface area of this cylinder = 157.14 Cm²

You might be interested in

On a coordinate plane, square P Q R S is shown. Point P is at (4, 2), point Q is at (8, 5), point R is at (5, 9), and point S is

sergey [27]

Answer:

(D)The midpoint of both diagonals is (4 and one-half, 5 and one-half), the slope of RP is 7, and the slope of SQ is Negative one-sevenths.

Step-by-step explanation:

Point P is at (4, 2),
Point Q is at (8, 5),
Point R is at (5, 9), and
Point S is at (1, 6)

Midpoint of SQ $=\frac{1}{2}(1+8,5+6)=(4.5,5.5)$

Midpoint of PR $=\frac{1}{2}(4+5,2+9)=(4.5,5.5)$

Now, we have established that the midpoints (point of bisection) are at the same point.

Two lines are perpendicular if the slope of one is the negative reciprocal of the other.

In option D

Slope of RP =7

Slope of SQ $=-\dfrac17$

Therefore, lines RP and SQ are perpendicular.

Option D is the correct option.

6 0

2 years ago

Determine the value of (tangent of 88 degrees, 22 minutes, and 45 seconds). In this case, minutes are 1/60 of a degree and secon

mariarad [96]

Answer:

c. 35.34015106

Step-by-step explanation:

As with many problems of this nature, you only need to get close to be able to choose the correct answer. 22 minutes 45 seconds is just slightly less than 1/2 degree (30 minutes), so the tangent value will be just slightly less than tan(88.5°) ≈ 38. The appropriate choice is 35.34015106.

If you need confirmation, you can find tan(88°) ≈ 29, so you know the answer will be between 29 and 38.

The above has to do with strategies for choosing answers on multiple-choice problems. Below, we will work the problem.

The angle is (in degrees) ...

88 + 22/60 +45/3600 = 88 + (22·60 +45)/3600 = 88 +1365/3600

≈ 88.3791666... (repeating) . . . . degrees

A calculator tells you the tangent of that is ...

tan(88.3791666...°) ≈ 35.3401510614

Many calculators will round that to 10 digits, as in the answer above. Others can give a value correct to 32 digits. Spreadsheet values will often be correct to 15 or 16 digits.

4 0

2 years ago

Frank has three times as many dollars as Deandra, and Charlie has 20 more dollars than Frank. If Charlie has $65, how much money

My name is Ann [436]

Answer:

$15

Step-by-step explanation:

Let Frank be f

Deandra be d and

Charlie be c

f = 3d ......(i)

c=$20+f.....(ii)

c=$65........(iii)

Equate (ii) and (iii)

$20+f = $65

f = $45.......(iv)

Equate (i) and (iv)

3d = $45

d = $15

Deandra has $15.

8 0

1 year ago

Read 2 more answers

I set a goal to drink 64 ounces of water day.If i drink 10 1/3 ounces in the morning,15 1/2 ounces at noon,and 20 5/6 at dinner

Vedmedyk [2.9K]

First find how much you've had. Make the fractions with similar denominaters: 1/3(2)=2/6, 1/2(3)=3/6, 5/6(1)=5/6. Now add the fractions: 2/6+3/6+5/6=10/6 or 1 4/6 or 1 2/3. Then add the whole numbers: 10+15+20+1=46. So you've had 46 2/3 oz now subtract that from how much you need: 64-46 2/3= 63 3/3-46 2/3=17 1/3. You still need 17 1/3 water :)

6 0

1 year ago

Let Y denote a geometric random variable with probability of success p. a Show that for a positive integer a, P(Y > a) = qa .

lakkis [162]

Answer:

a) For this case we can find the cumulative distribution function first:

$F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k$

So then by the complement rule we have this:

$P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a$

b) $P(Y>a)= q^a$

$P(Y>b) = q^b$

So then we have this using independence:

$P(Y> a+b) = q^{a+b}$

We want to find the following probability:

$P(Y> a+b |Y>a)$

Using the definition of conditional probability we got:

$P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)$

And we see that if a = 2 and b=5 we have:

$P(Y> 2+5 | Y>2) = P(Y>5)$

c) For this case we use independent identical and with the same distribution experiments.

And the result for part b makes sense since we are interest in find the probability that the random variable of interest would be higher than an specified value given another condition with a value lower or equal.

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

If we define the random of variable Y we know that:

$Y\sim Geo (1-p)$

Part a

For this case we can find the cumulative distribution function first:

$F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k$

So then by the complement rule we have this:

$P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a$

Part b

For this case we can use the result from part a to conclude that:

$P(Y>a)= q^a$

$P(Y>b) = q^b$

So then we have this assuming independence:

$P(Y> a+b) = q^{a+b}$

We want to find the following probability:

$P(Y> a+b |Y>a)$

Using the definition of conditional probability we got:

$P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)$

And we see that if a = 2 and b=5 we have:

$P(Y> 2+5 | Y>2) = P(Y>5)$

Part c

For this case we use independent identical and with the same distribution experiments.

8 0

2 years ago