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Andrews [41]
2 years ago
9

Which number is a solution of the inequality: B > 2.1

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
3 0

Answer:

C. 5 is solution of the inequality: B>2.1

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Simplify the following expression into the form a + bi, where a and b are rational numbers.
vagabundo [1.1K]
The answer is -16 - 10i.

Using the distributive property on the first part, we have:
-2i*7--2i*4i + (3+i)(-2+2i)
-14i+8i² +(3+i)(-2+2i)

Using FOIL on the last part,
-14i+8i²+(3*-2+3*2i+i*-2+i*2i)
-14i+8i²-6+6i-2i+2i²
-10i+8i²-6+2i²

Since we know that i = -1,
-10i+8(-1)-6+2(-1)
-10i-8-6-2
-16-10i
7 0
2 years ago
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For two events A and B, a student calculates that P(A and B) = 0.46 and P(B|A) = 0.31. Explain how you can tell that the student
ololo11 [35]
Conditional probability formula is:P ( A and B ) = P ( A ) · P ( B / A )0.46 = P ( A ) · 0.31P ( A ) = 0.46 : 0.31P ( A ) = 1.48And this is impossible because 0 ≤ P ( A ) ≤ 1The student obviously made a mistake.

3 0
2 years ago
How close are a meter and a yard? Convert, 1 meter into yards by using the fact that there are 100 centimeters in a meter, 2.54
Sveta_85 [38]

Answer:

To convert 1 meter into yards

Using the given facts : 100 centimeters in a meter, 2.54 centimeters in an inch, 12 inches in a foot, and 3 feet in a yard.

we can write these as;

1 m = 100 cm

1 inches = 2.54 cm

1 ft = 12 inches and

1 yard = 3 ft

1 ft = 12 inches

3 ft = 3 \times 12 = 36 inches

Since,

1 inches  = 2.54 cm

36 inches = 91.44 cm

Also,

1 m = 100 cm

or

1 cm = \frac{1}{100} m

then;

91.44 cm = \frac{91.44}{100} =0.9144 m

⇒ 1 yards = 0.9144 m

Divide both sides by 0.9144 we get;

1 meter = \frac{1}{0.9144} = 1.0936133 yards.

Therefore, the answer is, 1 m =  1.1 yards (nearest to tenth)


5 0
2 years ago
In the figure to the right, AE + DC = 1 1/5 cm, AB = 1 3/4 cm, DE = 1 1/4 cm, and BC = 1 3/10 cm. Find the perimeter of the figu
myrzilka [38]

https://www.omnicalculator.com/math/perimeter

5 0
2 years ago
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The sequence of transformations that can be performed on quadrilateral ABCD to show that it is congruent to quadrilateral GHIJ i
Marina86 [1]

First transformation.

Duadrilateral ABCD has vertices with such coordinates:

  • A(15,10);
  • B(15,20);
  • C(20,15);
  • D(20,5).

Apply a rotation by 90°counterclockwise around point A to this quadrilateral, then

  • A(15,10)→A'(15,10);
  • B(15,20)→B'(5,10);
  • C(20,15)→C'(10,15);
  • D(20,5)→D'(20,15).

Second transformation.

1. A reflection across the y axis has a rule:

(x,y)→(-x,y).

Then

  • A'(15,10)→A''(-15,10);
  • B'(5,10)→B''(-5,10);
  • C'(10,15)→C''(-10,15);
  • D'(20,15)→D''(-20,15).

2. A translation 20 units down has a rule:

(x,y)→(x,y-20).

Then

  • A''(-15,10)→G(-15,-10);
  • B''(-5,10)→H(-5,-10);
  • C''(-10,15)→I(-10,-5);
  • D''(-20,15)→J(-20,-5).

Answer: first blank -B, second blank - B.

4 0
2 years ago
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