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iren [92.7K]
2 years ago
8

A small community organization consists of 20 families, of which 4 have one child,8 have two children, 5 have three children, 2

have four children, and 1 has fivechildren. If one of these families is chosen at random, what is the probability it has`children,`= 1,2,3,4,5?
Mathematics
1 answer:
ELEN [110]2 years ago
3 0

Answer and Step-by-step explanation:

According to the situation, The probabilities for each one is given below:

As there are 20 families

So the probabilities for each one is

For four families have one child is

= \frac{4}{20}\\\\ = \frac{1}{5}

For eight families have two children is

= \frac{8}{20}\\\\ = \frac{2}{5}

For five families have three children is

= \frac{5}{20}\\\\ = \frac{1}{4}

For two families have four children is

= \frac{2}{20}\\\\ = \frac{1}{10}

For one family have five children is

= \frac{1}{20}

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Children under 10 years and older people over 65 years receive a discount on movie tickets. Let x represent the age of a person
mr_godi [17]

0<x<10

x>65

0<x<10 or x>65

4 0
2 years ago
James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
2 years ago
Workers have packed 1,400 glasses in 7 boxes. If they pack 3 more boxes, how many glasses will they have packed in all?
Alexandra [31]
2000


1box = 1400/7 = 200
200×3=600
1400+600=2000


Step-by-step explanation:
Given :Workers have packed 1,400 glasses in 7 boxes.
To Find :If they pack 3 more boxes, how many glasses will they have packed in all?
Solution:
Workers packed no. of glasses in 7 boxes = 1400
Workers packed no. of glasses in 1 box =
Workers packed no. of glasses in 3 boxes =
                                                                      =
So, initially they packed 1400 glasses
If they pack 3 more boxes so, the pack 600 glasses more
So, The total no. of glasses have packed by workers = 1400+600 = 2000
Hence they have packed 2000 glasses in all.
5 0
2 years ago
Q#1:The volume of a cube is 46656 cubic metres.Find the length of each side?
Lady_Fox [76]

Answer:

Step-by-step explanation:

1) To find the cube root of a number prime factorize

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Length of each side = 36 m

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-512 is a cube number

v) -17576 = (-26) * (-26)*(-26)

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3 0
1 year ago
(1 Convert the integral below to polar coordinates and evaluate the integral. ∫4/2√0∫16−y2√yxydxdy∫04/2∫y16−y2xydxdy Instruction
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Answer:

A = 0

B = π/4

C = 0

D = 4

Volume = 16

Step-by-step explanation:

∫BA∫DC∫AB∫CD is shown in the picture attached

4 0
2 years ago
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