My calculations got to a decimal so it’s about.
The regular hexagon ABCDEF rotates 240º counterclockwise about its center to form hexagon A′B′C′D′E′F′. Point C′ of the image co
incides with point ? of the preimage. Point D′ of the image coincides with point ? of the preimage. 
2 answers:
Answer:
Point C′ of the image coincides with point E of the preimage.
Point D′ of the image coincides with point F of the preimage.
Step-by-step explanation:
A translation counterclockwise 60° moves point A to F, F to E, E to D, et cetera. A translation counterclockwise 180° moves any vertex to the opposite vertex, so A moves to D, B to E, C to F and vice versa. Then, a translation counterclockwise 240° is a combination of the two aforementioned translations and moves A to C, F to B, E to A, D to F, C to E and B to D, creating the hexagon A′B′C′D′E′F′ (see figure attached).
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