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TEA [102]
1 year ago
8

Ten turns of a wire are helically wrapped around a cylindrical tube with outside circumference 4 inches and length 9 inches. The

ends of the wire coincide with ends of the same cylindrical element. Find the length of the wire. (a) 41 inches (b)36 inches (c) 40 inches (d) 90 inches
Mathematics
1 answer:
kari74 [83]1 year ago
8 0

Answer:

b) 36 inches

Step-by-step explanation:

Length  of the  wire = Outside circumference of the cylindrical tube * length of the cylinder

= 4 * 9

= 36 inches

Length of the wire will be same to the surface area of the cylinder

Surface area of cylinder = circumference * length

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Consider the function f(x)=(x+4)(x+2). Dilate f(x) by X to create a new function of a higher degree
Marat540 [252]

Answer:

Consider the function f (x) = (x +4) (x + 2).

Step-by-step explanation:

4 0
1 year ago
A quality control technician works in a factory that produces computer monitors. Each day, she randomly selects monitors and tes
jeka94

Answer:

There is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 300

p = 5% = 0.05

Alpha, α = 0.05

Number of dead pixels , x = 24

First, we design the null and the alternate hypothesis  

H_{0}: p = 0.05\\H_A: p > 0.05

This is a one-tailed(right) test.  

Formula:

\hat{p} = \dfrac{x}{n} = \dfrac{24}{300} = 0.08

z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

Putting the values, we get,

z = \displaystyle\frac{0.08-0.05}{\sqrt{\frac{0.05(1-0.05)}{300}}} = 2.384

Now, we calculate the p-value from excel.

P-value = 0.00856

Since the p-value is smaller than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

Thus, there is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.

5 0
1 year ago
A company makes traffic signs.One of their signs can be modeled by an equilateral triangle with a perimeter of 144 inches. The c
Mars2501 [29]

Answer:

The perimeter of the larger sign : 144*1,25= 180 inches

Side of the triangle= 180/3= 60 inches

square of the height= 60^(2) - 30^(2)= 2700 ( Pythagoras' theorem)

height= square root ( 2700)= 51,96

Step-by-step explanation:


6 0
2 years ago
Two galaxies are shown. Galaxy U: Dust, gas, and stars in the shape of a pinwheel, relatively small in size. Galaxy NGC 1427A: D
Pani-rosa [81]

Answer:

NGC 1427A has no general shape, so it is an irregular galaxy. U has a bulge in the center and arms, so it is a spiral galaxy. They are similar in that both contain plenty of dust and gas. Both also have active star-forming sites.

Step-by-step explanation: Got it right on the test

8 0
2 years ago
Read 2 more answers
If each term in the sum a1+a2+a3+...+an is either 7 or 77 and the sum equals 350, which of the following could be equal to n?A.
Svetlanka [38]

Answer:

C. 40

Step-by-step explanation:

Let us say there are x 7's and y 77's.

We have been given that each term in the sum a1+a2+a3+...+an is either 7 or 77 and the sum equals 350. We are asked to find the value of n.

Since the sum of all numbers is 350, so we can represent this information in an equation as:

7x+77y=350

The only integer solutions for the equation 7x+77y=350 are 10, 20, 30, 40, 50 .

So, there can be these many terms: 10 or 20 or 30 or 40 or 50 .

The given option only contains 40, so 40 would be the answer. For 40 terms to be there, there has to be 39 sevens and 1 seventy-seven.

Let us verify our answer.

7x+77y=350

7(39)+77(1)=350

273+77=350

350=350

Therefore, the total terms (n) could be equal to 40 and option C is the correct choice.

8 0
2 years ago
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