we know that
The measurement of <u>the external angle</u> is the semi-difference of the arcs it includes.
In this problem
![21\°=\frac{1}{2}[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=21%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20RU-arc%5C%20SU%5D)
Solve for the measure of arc SU
![42\°=[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=42%5C%C2%B0%3D%5Barc%5C%20RU-arc%5C%20SU%5D)


therefore
the answer is
The measure of the arc SU is 
Answer:
See below
Step-by-step explanation:
<h3>Continuation of the question</h3>
<u>Data in the table:</u>
<u>PH 4 5 6 7 8 9 10 11 </u>
<u>Bacteria 116 120 131 136 141 151 148 163</u>
- <em>Create a scatter plot to represent the data: Based on the data and your scatter plot, what do you think a good linear function would be to represent the data?</em>
<h3>Solution</h3>
<em>See attached for scatter plot</em>
We can see the chart is close to linear function. Let's build one based on data in the table
<u>The line will be in the form of:</u>
<u>If we use two points and get the equation</u>
<u>Finding the slope:</u>
- m = (141-116)/(8-4) = 25/4 = 6.25
<u>Then, finding y-intercept:</u>
- 116 = 6.25*4 + b
- b = 116 - 25 = 91
<u>So the line is:</u>
<em>Note: This is approximate best fit graph and it is attached as well. Exact formula for the line is built by using different method and is very close to the one above</em>
Answer:
The width of lot B is 11 feet, so option A is correct.
Step-by-step explanation:
Given:
- Two rectangular properties share a common side.
- Lot A is 33 feet wide and 42 feet long.
- The combined area of the lots = 1,848 square feet.
To find:
How many feet wide is Lot B?
Solution:
we know that, area of a rectangle is length x breadth
Then area of lot A = 33 x 42 = 1386 square feet.
And area of lot B = width x 42
Now, we are given that, total area = 1848
area of lot A + area of lot B = 1848
1386 + width x 42 = 1848
width x 42 = 1848 – 1386
width x 42 = 462

width = 11
Hence, the width of lot B is 11 feet, so option A is correct.