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olga55 [171]
2 years ago
13

#In Pokemon Go, a Pokemon is defined by several different #parameters. For simplicity in this problem, we'll say that #every Pok

emon is defined by two parameters: its name, a #string, and its power level, an integer. # #Create a class called Pokemon. The Pokemon class's #constructor should have two parameters (in addition to self): #the Pokemon's name and the Pokemon's power. These should be #assigned to attributes called 'name' and 'power'. # #The Pokemon class should also have a method called #would_defeat. would_defeat will have one parameter: an #instance of a _different_ Pokemon. would_defeat should #return True if this Pokemon's power is greater than the #other Pokemon's power, or False if not. #Add your code here!
Computers and Technology
2 answers:
MissTica2 years ago
8 0

Answer:

true

Explanation:

Semenov [28]2 years ago
5 0

Answer:

YUP

Explanation:

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I think the best one is voice recognition keyboards.


Would perfect work there



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Clara writes online articles based on world religions. Her articles have references to dates. Which HTML element will help her d
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Answer:

Available Options are :

A <b>

B <l>

C <body>

D <small>

Ans : A <b>

Explanation:

Normally AD and BC are written in bold letters.

for example : The terms anno Domini (AD) and before Christ (BC).

Within available option the best option to choose is <b>

The <body> element used to define the document body.

The <small> tag used to defines smaller text

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A DTP firm has published and printed flyers for an upcoming fundraising event. In which section of the flyer would you find the
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2 years ago
A feature on a new computer with Windows preinstalled. When you take it out of the box and turn it on, you will be greeted with
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Answer:

Explanation:

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2 years ago
a.Write a Python function sum_1k(M) that returns the sum푠푠= ∑1푘푘푀푀푘푘=1b.Compute s for M = 3 by hand and write
stealth61 [152]

Answer:

def sum_1k(M):

   s = 0

   for k in range(1, M+1):

       s = s + 1.0/k

   return s

def test_sum_1k():

   expected_value = 1.0+1.0/2+1.0/3

   computed_value = sum_1k(3)

   if expected_value == computed_value:

       print("Test is successful")

   else:

       print("Test is NOT successful")

test_sum_1k()

Explanation:

It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.

- Inside the <em>sum_1k(M)</em>, iterate from 1 to M and calculate-return the sum of the expression.

- Inside the <em>test_sum_1k(),</em> calculate the <em>expected_value,</em> refers to the value that is calculated by hand and <em>computed_value,</em> refers to the value that is the result of the <em>sum_1k(3). </em>Then, compare the values and print the appropriate message

- Call the <em>test_sum_1k()</em> to see the result

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1 year ago
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