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rewona [7]
2 years ago
13

The picture below shows a right-triangle-shaped charging stand for a gaming system: The side face of a charging stand is a right

triangle labeled ABC. The measure of angle ACB is 90 degrees, and the measure of angle ABC is 60 degrees. The length, BC, of the side adjacent to the angle ABC is 8 inches. Which expression shows the length of side AB? 8(cos 60°) 8 over sin 60 degrees 8 over cos 60 degrees 8(tan 60°)

Mathematics
1 answer:
mamaluj [8]2 years ago
3 0

Answer:

AB = 8/ cos 60

Step-by-step explanation:

We want to find the hypotenuse AB

Since we have a right triangle

cos theta = adj/ hyp

cos 60 =  8/ AB

AB cos 60 = 8

AB = 8/ cos 60

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A random sample of 15 observations from the first population revealed a sample mean of 350 and a sample standard deviation of 12
marissa [1.9K]

Answer:

Step-by-step explanation:

Hello!

You have two random samples obtained from two different normal populations.

Sample 1

n₁= 15

X[bar]₁= 350

S₁= 12

Sample 2

n₂= 17

X[bar]₂= 342

S₂= 15

At α: 0.05 you need to obtain the p-value for testing variances for a one tailed test.

If the statistic hypotheses are:

H₀: σ₁² ≥ σ₂²

H₁: σ₁² < σ₂²

The statistic to test the variances ratio is the Stenecor's-F test. F_{H_0}=(\frac{S^2_1}{Sigma^2_1}) * (\frac{S^2_2}{Sigma^2_2} )~F_{n_1-1;n_2-1}

F_{H_0}= \frac{(12)^2}{(15)^2} * 1= 0.64

The p-value is:

P(F_{14;16}≤0.64)= 0.02

I hope it helps!

7 0
2 years ago
It is known that 70% of the customers in a sporting goods store purchase a pair of running shoes. a random sample of 25 customer
NikAS [45]

Let x be the discrete random variable whose value is the number of successes in n trials.

The probability distribution function for x of the binomial distribution B(n,p) is defined as

B(n,p)= nC_xp^x(1-p)^{n-x}

Given that the random sample size is n=25

let x represent number of customers who purchase running shoes

Let "p" be the probability of customers in a sporting goods store purchase a pair of running shoes.

It is given that 70% of the customers in a sporting goods store purchase a pair of running shoes.

Thus p=\frac{70}{100}=0.7

Thus the Probability distribution of x is given by

P(X=x)= 25C_x(0.7)^x(1-0.7)^{25-x}, where x=0,1,2,3,...,25.

8 0
1 year ago
"Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad lengt
Westkost [7]

Answer:

a) \bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b) Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c) P(\bar X >31.25)=0.006=0.6\%

d) P(\bar X >28.25)=0.9997=99.97\%

e) P(28.25

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variabl length of advertisements produced by Majesty Video Production Inc. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =30,\sigma =2)

We take a sample of n=16 . That represent the sample size.

a. What can we say about the shape of the distribution of the sample mean time?

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b. What is the standard error of the mean time?

The standard error is given by this formula:

Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c. What percent of the sample means will be greater than 31.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >31.25)=1-P(\bar X

d. What percent of the sample means will be greater than 28.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula is given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >28.25)=1-P(\bar X

e. What percent of the sample means will be greater than 28.25 but less than 31.25 seconds?"

We want this probability:

P(28.25

3 0
2 years ago
Lupe can ride her bike at a rate of 20 mph when there is no wind. On one particular day, she rode 2 miles against the wind and n
miskamm [114]
Time = 3 miles / (20 mph - wind velocity)
time = 2 miles / (20 mph + wind velocity)

3 miles / (20 mph + wind velocity) = 2 miles / (20 mph - wind velocity)

3/2 =  (20 mph + wind velocity) / (20 mph - wind velocity)

1.5 =  (20 mph + wv) / (20 mph -wv)

30 mph -1.5wv = 20 mph -wv

10 mph = 2.5 wv

wind velocity = 4 mph


3 0
1 year ago
Read 2 more answers
The average rate of the first part of Yi’s walk on a park loop was 4 miles per hour. She then met up with a friend and the two w
irakobra [83]
So she walked during this time with <span>4 miles per hour (x*4)

during the rest of the way (which is 0.7-x, as the whole way took her 42 minutes, so the rest is 0.7-x) she walked with 5 miles per hour - the distance was (0..7-x)*5 m/h



the total distance was 3 miles, so if we sum the two distances, we will get 3 miles:

x*4+ (0.7-x)*5=3

let's remove the bracket:

4x+0.7*5-5x=3
</span>
<span>4x+3.5-5x=3

subtract 3.5 from both sides:
4x-5x=3-3.5
-x=-0.5
 
multiply both sides by  (-1)
x=0.5:

so she walked for half an hour alone, that is for 30 minutes!</span>
8 0
1 year ago
Read 2 more answers
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