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Anettt [7]
2 years ago
5

The average rate of the first part of Yi’s walk on a park loop was 4 miles per hour. She then met up with a friend and the two w

alked the rest of the way at an average rate of 5 miles per hour. The entire 3-mile walk took Yi 42 minutes (0.7 hour). Which equation can be used to solve for x, the time in hours that Yi spent walking before meeting her friend?
Mathematics
2 answers:
irakobra [83]2 years ago
8 0
So she walked during this time with <span>4 miles per hour (x*4)

during the rest of the way (which is 0.7-x, as the whole way took her 42 minutes, so the rest is 0.7-x) she walked with 5 miles per hour - the distance was (0..7-x)*5 m/h



the total distance was 3 miles, so if we sum the two distances, we will get 3 miles:

x*4+ (0.7-x)*5=3

let's remove the bracket:

4x+0.7*5-5x=3
</span>
<span>4x+3.5-5x=3

subtract 3.5 from both sides:
4x-5x=3-3.5
-x=-0.5
 
multiply both sides by  (-1)
x=0.5:

so she walked for half an hour alone, that is for 30 minutes!</span>
worty [1.4K]2 years ago
5 0

Answer:

D, 4x + 5(0.7 – x) = 3.

Step-by-step explanation:

yw egen2020

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Consider the following formula used to estimate height, h, of a seedling after w weeks since planting:
svp [43]

Answer:

Option B. w=5h-8

Step-by-step explanation:

we have

h=(\frac{1}{5})w+(\frac{8}{5})

Solve for w

That means ----> isolate the variable w

Multiply by 5 both sides to remove the fraction

5h=w+8

subtract 8 both sides

5h-8=w+8-8

5h-8=w

Rewrite

w=5h-8

4 0
2 years ago
Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni
trasher [3.6K]

For this case, the first thing we must do is define variables.

We have then:

t: the time in minutes

k: the number of kilometers

The relationship between both variables is direct.

Therefore, the function is:

k (t) = c * t

Where, "c" is a constant of proportionality.

To determine "c" we use the following data:

After running for 18 minutes, she completes 2 kilometers.

Substituting values:

2 = c * 18

Clearing c we have:

c = \frac{2}{18}

c = \frac{1}{9}

Then, the equation is given by:

k (t) = \frac{1}{9} * t

Answer:

An equation that can be used to represent k, the number of kilometers Julissa runs in t minutes is:

k (t) = \frac{1}{9} * t

7 0
2 years ago
Read 2 more answers
Mr.Hollins determines that he gives away $800 each month. If he gives away 16% of his budget, how much is his overall budget?
oee [108]

\frac{800}{x}  = \frac{16\%}{100\%}  \\  \frac{80000}{16}  =  \frac{16x}{16}  \\ 5000 = x
5 0
2 years ago
Pete traveled 1,380 miles in two days.The first day , he traveled 1.5 times as far as he did the second day . How many miles did
ahrayia [7]
Let s be the distance traveled the second day.

1.5s+s=1380

2.5s=1380

s=552

So on the first day he traveled 1380-552=828 miles.
6 0
2 years ago
Read 2 more answers
A print shop purchases a new printer for $25,000. The equipment depreciates at a rate of 5% each year. The relationship between
Pani-rosa [81]

Answer:

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

Step-by-step explanation:

Since the printer depreciates at a rate of 5% per year, I believe the stated equation is miss typed. Therefore I'll answer this with the correct equation that would represent that setting:

y(x) = 25,000*0.95^x

In the first year the value of the printer is:

y(1) = 25,000*0.95^1 = 23,750

On the second year the value of the printer is:

y(2) = 25,000*0.95^2 = 22,562.5\\

On the third year the value of the printer is:

y(3) = 25,000*0.95^3 = 21,434.38\\

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

5 0
2 years ago
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