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ivann1987 [24]
2 years ago
7

Fiona started her study of bacteria growth with 1,000 bacteria in a petri dish. After 1 hour, the count was increased to 1,800.

After 2 hours, the count was 3,240. After the third hour showed a count of 5,832, Fiona wrote an equation to represent the exponential growth of the bacteria. What exponential growth function did Fiona write?
Mathematics
2 answers:
SOVA2 [1]2 years ago
5 0
F (x)=1000×1.8^x is the equation.
Sphinxa [80]2 years ago
4 0

Answer:

The exponential growth function is f(x) = 1000 \cdot (1.8)^x

Step-by-step explanation:

Given : Fiona started her study of bacteria growth with 1,000 bacteria in a Petri dish. After 1 hour, the count was increased to 1,800. After 2 hours, the count was 3,240. After the third hour showed a count of 5,832. Fiona wrote an equation to represent the exponential growth of the bacteria.

To find : What exponential growth function did Fiona write?

Solution :

The general form of an exponential function is y=ab^x....(1)

Where, a is the initial value and r is the rate factor.

According to question,

Initial value is a=1000

After 1 hour, the count was increased to 1,800.

After 2 hours, the count was 3,240.

After the third hour showed a count of 5,832,

Let x represents the time in hour and y represents thee count of bacteria.

Taking the points (1,1800), (2,3240).

Substitute in equation (1),

1800 = ab   .....(2)

3240 =ab^2 ....(3)

Divide equation (3) by (2),

\frac{3240}{1800}=\frac{ab^2}{ab}

1.8=b

The rate factor is b=1.8

Now, Substitute the value of a and b in equation (1)

f(x) = 1000 \cdot (1.8)^x

Therefore, The exponential growth function is f(x) = 1000 \cdot (1.8)^x

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Read 2 more answers
The table shows some values of a function of the form y = ax2 + bx + c.
natali 33 [55]

Answer:

Value of constant term c is (-4)

Step-by-step explanation:

The given table represents a function which is in the form of a quadratic equation,

y = ax² + bx + c

We choose three points (3, -10), (4, -16) and (5, -24) from the table and satisfy the equation to get the values of a, b, and c.

For point (3, -10)

-10 = a(3)² + 3b + c

9a + 3b + c = -10 -------(1)

For point (4, -16)

-16 = a(4)² + 4b + c

16a + 4b + c = -16 ------(2)

For point (5, -24)

-24 = a(5)² + 5b + c

25a + 5b + c = -24 -----(3)

Equation (1) - equation (2)

(9a + 3b + c) - (16a + 4b + c) = -10 + 16

-7a - b = 6

7a + b = -6 ------(4)

Equation (2) - equation (3)

(16a + 4b + c) - (25a + 5b + c) = -16 + 24

-9a - b = 8

9a + b = -8 -------(5)

Equation (4) - Equation (5)

(7a + b) - (9a + b) = -6 + 8

-2a = 2

a = -1

From equation (4),

-7(1) + b = -6

b = -6 + 7

b = 1

From equation (1)

9(-1) + 3(1) + c = -10

-9 + 3 + c = -10

c = -10 + 6

c = -4

Therefore, the value of constant term c is (-4).

5 0
1 year ago
Find the range of y=3/2cos4x-1
MrRissso [65]

Answer:

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

Step-by-step explanation:

Smallest value of cos α = - 1,

largest value of cos α = 1.

When cos 4x = - 1,  y=3/2cos4x-1 = 3/2*(-1) - 1 = - 5/2 = - 2 1/2 = - 2.5

When cos 4x = 1,  y=3/2cos4x-1 = 3/2*1 - 1 = 1/2 = 0.5

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

5 0
1 year ago
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