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vovikov84 [41]
2 years ago
6

Select the correct answer. The velocity of a train relative to the ground is represented by the distance from A to B in the diag

ram. The velocity of a ball thrown inside the train at an angle of 66° relative to the train is represented by the distance from B to C. What is the distance from A to C (the velocity of the ball relative to the ground), correct to two decimal places? Assume that all the points in the diagram lie in the same plane. A. 21.14 m/s B. 18.03 m/s C. 17.20 m/s D. 15.00 m/s

Mathematics
1 answer:
Alex777 [14]2 years ago
7 0

Answer:

Step-by-step explanation:

we use cosine formula

2×15×10×cos(180-66)=15²+10²-AC²

-300 cos 66=225+100-AC²

AC²=325+300 cos 66

AC=\sqrt{325+300 cos 66} \approx 21.14 ~m/s

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RANDOMLY CHOOSING TWO POTENTIAL CLIENTS
gregori [183]
Let <span>Jacob, Carol, Geraldo, Meg, Earvin, Dora, Adam, and Sally be represented by the letters J, C, G, M, E, D, A, and S respectively. </span>

<span>In part IV we are asked:

</span><span>What is the sample space of the pairs of potential clients that could be chosen?
</span><span>
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{(J, C), (J, G), (J, M), (J, E), (J, D), (J, A), (J, S)

          , </span>(C, G), (C, M), (C, E), (C, D), (C, A), (C, S)
<span>                   
</span>                      , (G, M), (G, E), (G, D), (G, A), (G, S)
<span>             
                                    ,</span>(M, E), (M, D), (M, A), (M, S)    
<span> 
                                               , </span>(E, D),  (E, A),  (E, S) <span>   
                                                          
                                                           , </span>(D, A), (D, S)
              
                                                                       , (A, S).}

We can check that the number of the elements of the sample space, n(S) is 

1+2+3+4+5+6+7=28.


This gives us the answer to the first question: <span>How many pairs of potential clients can be randomly chosen from the pool of eight candidates? 

(Answer: 28.)


II) </span><span>What is the probability of any particular pair being chosen?
</span>
The probability of a particular pair to be picked is 1/28, as there is only one way of choosing a particular pair, out of 28 possible pairs.

III) <span>What is the probability that the pair chosen is Jacob and Meg or Geraldo and Sally? 

The probability of choosing (J, M) or (G, S) is 2 out of 28, that is 1/14.


Answers:

I) 28
II) 1/28</span>≈0.0357
III) 1/14≈0.0714
IV)


{(J, C),  (J, G), (J, M),  (J, E),   (J, D),  (J, A),   (J, S)
          , (C, G), (C, M), (C, E),   (C, D), (C, A),  (C, S)
                      , (G, M), (G, E),  (G, D), (G, A),  (G, S)
                                   ,(M, E),  (M, D), (M, A),  (M, S)    
                                               , (E, D),  (E, A),  (E, S)    
                                                            , (D, A), (D, S)
                                                                        , (A, S).}
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