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Sergio [31]
2 years ago
15

Please Help ;-;" :Mr. Gordon’s science class is studying blood types. The table below shows the probability that a person living

in the US has a particular blood type. ( Type 0=9/20) (Type A=41/100) (Type B=1/10) (Type AB=1/25) What is the probability that three students selected randomly from the class will have A, B, and AB blood, respectively? Explain how you would solve this problem.
Mathematics
2 answers:
Illusion [34]2 years ago
7 0

Answer:

The probability of 3 students having blood type A is 1.23 , having blood type B is 0.3 and having blood type AB is 0.12

Step-by-step explanation:

Multiple the total selected nuber with the types .

eimsori [14]2 years ago
6 0

Answer: The probability of 3 students having blood type A is 1.23 , having blood type B is 0.3 and having blood type AB is 0.12

Step-by-step explanation:

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If g = 77 cm and h = 85 cm, what is the length of f? My formula is a Right-Triangle.
Sedbober [7]
If we are looking for the hypotenuse the answer is, 114.69. If the h is the hypotenuse then you would have 36 for leg b. 
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What is the volume of the prism? 1080 cm 2700 cm 3240 cm 6480 cm
makkiz [27]

Answer:

Volume of prism = 3,240 cm³

Step-by-step explanation:

GIven.

Hexagonal prism.

Side of base(b) = 12cm

Height of prism = 9cm

Height of base (h)= 10cm

Find:

The volume of the prism.

Computation:

Area of base of hexagonal prism = n/2[bh]

Area of base of hexagonal prism = 6/2[(12)(10)]

Area of base of hexagonal prism = 360 cm²

The volume of prism = Area of base of hexagonal prism × Height of prism

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Volume of prism = 3,240 cm³

3 0
2 years ago
How do you write 125.06 million dollars in at least four different ways.
Ludmilka [50]
$125,060,000

one-hundred twenty-five million, and sixty thousand dollars

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125.06 million dollars, if you can use the number in the question.
5 0
2 years ago
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In triangle FGH, FG = 12.3 cm, GH = 10.6 cm, Measure of angle G = 80 degrees, and Measure of angle H = 55 degrees. If Triangle A
aalyn [17]

Question:

In triangle FGH, FG = 12.3 cm, GH = 10.6 cm, m angle G=80 degrees, and m angle H=55 degrees. If triangle ABC GHF, which statement is true?

(A) AB = 12.3 cm

(B) AB = 10.6 cm

(C) m∠C = 55°

(D) m∠C = 80°

Answer:

Option B:

AB = 10.6 cm

Solution:

The image of the triangle is attached below.

In ΔFGH,

FG = 12.3 cm, GH = 10.6 cm, m∠G = 80° and m∠H = 55°

Option A: AB = 12.3 cm

Given ΔGHF \sim ΔABC.

Corresponding parts of congruence triangles are congruent.

GH = AB = 10.6 cm

So, option A is not true.

Option B: AB = 10.6 cm

Already proved in option A that AB = 10.6 cm

So, option B is true.

Option C: m∠C = 55°

ΔGHF \sim ΔABC

Corresponding parts of congruence triangles are congruent.

m∠G = m∠A = 80°

m∠H = m∠B = 55°

Sum of the angles of a triangle = 180°

⇒ m∠A + m∠B + m∠C = 180°

⇒ 80° + 55° + m∠C = 180°

⇒ m∠C = 180° – 80° – 55°

⇒ m∠C = 45°

So, option C is not true.

Option D: m∠C = 80°

Already proved in option C that m∠C = 45°.

So, option D is not true.

Hence option B is the true statement that AB = 10.6 cm.

7 0
2 years ago
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A rectangular portrait measures 50cm by 70cm. It is surrounded by a rectangular frame of uniform width. If the area of the frame
snow_tiger [21]

Let us assume uniform width = x cm wide.

Length of rectangular portrait = 50cm and width of rectangular portrait = 70cm.

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We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.

Total area of the rectangle made by frame would be =  (2x+50) * (2x+70)

We know,

Actual area of frame = Area of rectangle made by frame -  area of rectangular portrait.

We also given "the area of the frame is the same as the area of the portrait."

We can setup an equation now,

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Subtracting 3500 from both sides, we get

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0 = (2x+50) * (2x+70) -7000.

FOIL (2x+50) * (2x+70), we get

0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.

0 = 4x^2 +140x +100x +3500 -7000.

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Dividing whole equation by 4, we get

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Applying quadratic formula =\frac{-b\pm \sqrt{b^2-4ac}}{2a}, we get

=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}

x=\frac{-60+\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}=5\left(\sqrt{71}-6\right)

x=\frac{-60-\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}:\quad -5\left(6+\sqrt{71}\right)

We cant take negative value.

So, x=5\left(\sqrt{71}-6\right)=12.13

We could take approximately 12 cm.



7 0
2 years ago
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