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Nezavi [6.7K]
2 years ago
12

Astronomers were at first surprised to find complicated molecules in the interstellar medium. They thought ultra-violet light fr

om stars would break apart such molecules. What protects the molecules we observe from being broken apart
Physics
1 answer:
jeka57 [31]2 years ago
8 0

Answer:

The dust present in the clouds.

Explanation:

The complicated composition molecules that can be found in space are generally associated with clouds of dust. The significant amount of dust in these clouds provides protection not only for these molecules, but for any body that makes up or is associated with dust clouds.

It is exactly this dust that protects the molecules against the action of ultraviolet rays.

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The center of a long frictionless rod is pivoted at the origin and the rod is forced to rotate at a constant angular velocity Q
Doss [256]

Answer:

The answers can be found attached.

7 0
2 years ago
A rare and valuable antique chest is being moved into a truck using a 4.00 m long ramp. the kj weight of the chest plus packing
Lisa [10]

First let us calculate for the angle of inclination using the sin function,

sin θ = 1 m / 4 m

θ = 14.48°

 

Then we calculate the work done by the movers using the formula:

W = Fnet * d

 

So we must calculate for the value of Fnet first. Fnet is force due to weight minus the frictional force.

Fnet = m g sinθ – μ m g cosθ

Fnet = 1,500 sin14.48 – 0.2 * 1,500 * cos14.48

Fnet = 84.526 N

 

So the work exerted is equal to:

W = 84.526 N * 4 m

<span>W = 338.10 J</span>

7 0
2 years ago
Init. A
Gekata [30.6K]

Answer:

v = 1/3 m / s = 0.333 m / s

in the direction of the truck

Explanation:

The average speed is defined by the variation of the position between the time spent

           v = Δx / Δt

since the position is a vector we must add using vectors, we will assume that the displacement to the right is positive, the total displacement is

           Δx = 20 - 15 +20

           Δx = 25 m

therefore we calculate

         v = 25/75

         v = 1/3 m / s = 0.333 m / s

in the direction of the truck

7 0
2 years ago
Four students measured the acceleration of gravity. The accepted value for their location is 9.78m/s2. Which student’s measureme
Lisa [10]

On comparing values , we see that student which has the largest percent error is <u>A. Student 4: 9.61 m/s2 .</u>

<u>Explanation:</u>

Here, we have Four students measured the acceleration of gravity. The accepted value for their location is 9.78m/s2. Let's calculate which student’s measurement has the largest percent error :

<u>A. Student 4: 9.61 m/s2 </u>

Percentage of error  = \frac{9.78-9.61}{9.78} (100) = 1.738% %.

<u>B. Student 3: 9.88 m/s2 </u>

Percentage of error  = \frac{9.88-9.78}{9.78} (100) = 1.022% %.

<u>C. Student 2: 9.79 m/s2 </u>

Percentage of error  = \frac{9.79-9.78}{9.78} (100) = 0.1022%% .

<u>D. Student 1: 9.78 m/s2</u>

Percentage of error  = \frac{9.78-9.61}{9.78} (100) = 0%% .

On comparing values , we see that student which has the largest percent error is <u>A. Student 4: 9.61 m/s2 .</u>

4 0
2 years ago
How much heat is released when 432 g of water cools down from 71'c to 18'c?
maria [59]
The heat released by the water when it cools down by a temperature difference \Delta T is
Q=mC_s \Delta T
where
m=432 g is the mass of the water
C_s = 4.18 J/g^{\circ}C is the specific heat capacity of water
\Delta T =71^{\circ}C-18^{\circ}C=53^{\circ} is the decrease of temperature of the water

Plugging the numbers into the equation, we find
Q=(432 g)(4.18 J/g^{\circ}C)(53^{\circ}C)=9.57 \cdot 10^4 J
and this is the amount of heat released by the water.
7 0
2 years ago
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