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Alona [7]
2 years ago
15

Now assume that the boat is subject to a drag force fd due to water resistance. is the component of the total momentum of the sy

stem parallel to the direction of motion still conserved?
Physics
2 answers:
gogolik [260]2 years ago
6 0

No

<h2>Further Explanation </h2>

The law of conservation of momentum states that "if there is no external force acting on the system, then the total momentum just before is equal to the total momentum after the collision". when using this equation, we must pay attention to the direction of the speed of each object.

The law of conservation of momentum is one of the basic laws in physics. This law states that "the total momentum of two objects before the collision is the same after a collision". This statement implies that the total momentum value when objects collide is constant or unchanged. To understand this law, we can begin by understanding Newton's Third Law of Action and Reaction.

The force acting on each colliding object occurs over a period of time. Regardless of the length of time the force contact occurs, this time interval is the same for object 1 and object 2. This means that the time interval between the workings of the forces from object 1 to object 2 is the same as the time interval for the workforce of object 2 to object 1.

As a consequence of the forces acting on the two objects are equal/opposite direction and the time interval between the occurrence of the force is also the same, then the impulse that occurs on the two objects is the same value and opposite direction.

From the theory of impulse-momentum change, that the impulse that occurs in an object is the same as its momentum change. Thus, because every object experiences an impulse that is equally large and opposite in direction, then logically each object also experiences changes in momentum that are as large and opposite.

Learn more

 The law of conservation of momentum brainly.com/question/3262217

Details

Grade:  High School

Subject:  Physics

keywords: Momentum, impulse.

DochEvi [55]2 years ago
4 0
Based on the given details with this question, I can say that the direction of motion is not conserved. This is because the boat is subjected to an external force because of water resistance. So, the answer for this question would be NO.
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A system delivers 1275 j of heat while the surroundings perform 855 j of work on it. calculate ∆esys in j.
kakasveta [241]
The first law of thermodynamics says that the variation of internal energy of a system is given by:
\Delta U = Q + W
where Q is the heat delivered by the system, while W is the work done on the system.

We must be careful with the signs here. The sign convention generally used is:
Q positive = Q absorbed by the system
Q negative = Q delivered by the system
W positive = W done on the system
W negative = W done by the system

So, in our problem, the heat is negative because it is releaed by the system: 
Q=-1275 J
while the work is positive because it is performed by the surrounding on the system:
W=+855 J

So, the variation of internal energy of the system is
\Delta U = -1275 J+855 J=-420 J
6 0
2 years ago
An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west. It start
FrozenT [24]

Answer:

  • The total distance traveled is 28 inches.
  • The displacement is 2 inches to the east.

Explanation:

Lets put a frame of reference in the problem. Starting the frame of reference at the point with the 0-inch mark, and making the unit vector \hat{i} pointing in the west direction, the ant start at position

\vec{r}_0 = 16 \ inch \ \hat{i}

Then, moves to

\vec{r}_1 = 29 \ inch \ \hat{i}

so, the distance traveled here is

d_1 = |\vec{r}_1 - \vec{r}_0  | = | 29 \ inch   \ \hat{i} - 16 \ inch   \ \hat{i}  |

d_1 =  | 13 \ inch   \ \hat{i}  |

d_1 =  13 \ inch

after this, the ant travels to

\vec{r}_2 = 14 \ inch \ \hat{i}

so, the distance traveled here is

d_2 = |\vec{r}_2 - \vec{r}_1  | = | 14 \ inch   \ \hat{i} - 29 \ inch   \ \hat{i}  |

d_2 =  | - 15 \ inch   \ \hat{i}  |

d_2 =  15 \ inch

The total distance traveled will be:

d_1 + d_2 = 13 \ inch + 15 \ inch = 28 \ inch

The displacement is the final position vector minus the initial position vector:

\vec{D}=\vec{r}_2 - \vec{r}_1

\vec{D}= 14 \ inch   \ \hat{i} - 16 \ inch \ \hat{i}

\vec{D}= - 2 \ inch \ \hat{i}

This is 2 inches to the east.

6 0
2 years ago
You are pulling your little sister on her sled across an icy (frictionless) surface. When you exert a constant horizontal force
Tpy6a [65]

Answer:

Mass of Little Sister = 44.17 kg

Explanation:

From Newton's second law of motion, the magnitude of force applied on the sled is given by the following formula:

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m = Mass of Sled + Mass of Little Sister = 8 kg + Mass of Little Sister

Therefore,

120 N = (2.3 m/s²)(8 kg + Mass of Little Sister)

(120 N)/(2.3 m/s²) = 8 kg + Mass of Little Sister

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jasenka [17]

Answer:

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Nikitich [7]
<h2>Answer: B. Gravitational potential energy </h2>

Explanation:

<em>The gravitational potential energy is the energy that a body or object possesses, due to its position in a gravitational field. </em>

That is why this energy depends on the relative height of an object with respect to some point of reference and associated with the gravitational force.

In the case of the <u>Earth</u>, in which  <u>the gravitational field is considered constant</u>, the value of the gravitational potential energy U_{p} will be:

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Where m is the mass of the object, g the acceleration due gravity and h the height of the object.

As we can see, the value of U_{p} is directly proportional to the height.

6 0
2 years ago
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