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2 years ago

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Matt Kaminsky bought a Volvo which is 3 3/4 times as expensive as the car his parents bought. If his parents paid $8,000 for the

irs, what is the cost of Matt's car?

1 answer:

Mice21 [21]2 years ago

8 0

Matt's car was bought for $30,000.

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A baby otter was born 3/4 of a month early. At birth it's weight was 7/8 kilograms which is 9/10 kilogram less than the average

Assoli18 [71]

Answer:

The average weight of new born otter was, $1\frac{31}{40}$

Step-by-step explanation:

Let average weight of new born otter be x.

As per the given statement: At birth it's weight was 7/8 kilograms which is 9/10 kilogram less than the average weight of a new born otter in the aquarium

" $\frac{9}{10}$ kg less than average weight of a new born otter" means $x-\frac{9}{10}$

As per the given information, we have;

$\frac{7}{8} = x -\frac{9}{10}$

Add $\frac{9}{10}$ both sides, we have;

$\frac{7}{8} + \frac{9}{10} = x$

Take LCM of 8 and 10 is, 40

⇒ $\frac{35+36}{40}=x$

Simplify:

$x = \frac{71}{40} = 1\frac{31}{40}$

Therefore, the average weight of new born otter was, $1\frac{31}{40}$

6 0

2 years ago

Read 2 more answers

The temperature of an enclosure for a pet corn snake should be an average of 81° F. For the well-being of the corn snake, the te

mario62 [17]

Answer: |81-x|<5

Step-by-step explanation:

Given: Temperature of an enclosure for a pet corn snake should be an average of 81° F.

Temperature in the enclosure should not vary by more than 5° F.

Let x= Temperature in the enclosure

Then, difference between average and current temperature should less the 5.

i.e. |81-x|<5 (required absolute value equation )

hence, the absolute value equation could be used to determine the minimum and maximum temperatures recommended for the corn snake enclosure:

|81-x|<5

4 0

2 years ago

Which expressions are equivalent to RootIndex 3 StartRoot 128 EndRoot Superscript x? Select three correct answers.

vodka [1.7K]

Answer:

<h3>- 128 Superscript StartFraction 3 Over x EndFraction </h3><h3>- (4RootIndex 3 StartRoot 2 EndRoot)x </h3><h3>- (4 (2 Superscript one-third Baseline) ) Superscript x</h3><h3>Step-by-step explanation:</h3>

Given the indicinal equation $(\sqrt[3]{128} )^{x}\\$

According to one of the law of indices,

$(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}$

Applying this law to the question;

$(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )$

The following are therefore true based on the following calculation

128 Superscript StartFraction 3 Over x EndFraction

(4RootIndex 3 StartRoot 2 EndRoot)x

(4 (2 Superscript one-third Baseline) ) Superscript x

5 0

2 years ago

Read 2 more answers

Which graph shows data whose r-value is most likely closest to 1?

Aleks04 [339]

Answer:

B on ed 2020

Step-by-step explanation:

an r value of 1 would be a graph that has a linear line going up one then

to the right one so the closest to that is the 2nd graph (B)

4 0

2 years ago

Read 2 more answers

Which represents a quadratic function? f(x) = −8x3 − 16x2 − 4x f (x) = three-quarters x 2 + 2x − 5 f(x) = StartFraction 4 Over x

tatyana61 [14]

Answer:

$2.\ f(x) = \frac{3}{4}x^2 + 2x - 5$

Step-by-step explanation:

Given

$f(x) = -8x^3 - 16x^2 - 4x\\f(x) = \frac{3}{4}x^2 + 2x - 5\\f(x) = \frac{4}{x^2} - \frac{2}{x} + 1\\f(x) = 0x^2 - 9x + 7$

Required

Which of the above is a quadratic function

A quadratic function has the following form;

$ax^2 +bx + c = 0 \ where \ a\neq 0$

So, to get a quadratic function from the list of given options, we simply perform a comparative test of each function with the form of a quadratic function

$1.\ f(x) = -8x^3 - 16x^2 - 4x$

This is not a quadratic function because it follows the form $f(x) = ax^3 + bx^2 + c$ and this is different from $ax^2 +bx + c = 0 \ where \ a\neq 0$

$2.\ f(x) = \frac{3}{4}x^2 + 2x - 5$

This function has an exact match with $ax^2 +bx + c = 0 \ where \ a\neq 0$

By comparison; $a = \frac{3}{4}\ b = 2\ and\ c = -5$

$3.\ f(x) = \frac{4}{x^2} - \frac{2}{x} + 1$

This is not a quadratic function because it follows the form $f(x) = \frac{a}{x^2} + \frac{b}{x} + c$ and this is different from $ax^2 +bx + c = 0 \ where \ a\neq 0$

$4.\ f(x) = 0x^2 - 9x + 7$

This is not a quadratic function because it follows the form $f(x) = ax^2 +bx + c = 0\ but\ a = 0$

Unlike the quadratic function where $a\neq 0$

So, from the list of given options, only $2.\ f(x) = \frac{3}{4}x^2 + 2x - 5$ satisfies the given condition

5 0

2 years ago