2x - 3y = 16 5x - 3y = 13 solve the system of equations
1 answer:
You might be interested in
Actually there is enough information to solve this problem. First, let us find the total per row and per column.
(see attached pic)
P(Grade 10 | opposed) with P(opposed | Grade 10)
P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)
P(Grade 10 | opposed) = 13 / 41 = 0.3171
P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)
P(opposed | Grade 10) = 13 / 32 = 0.4063
Therefore:
P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10), hence they are dependent events.
Answer:
P(Grade 10 | opposed) < P(opposed | Grade 10)
Answer:
On a coordinate plane, 2 quadrilaterals are shown. The larger quadrilateral has points (negative 5, 3), (1, 3), (4, 0), (negative 2, 0). The smaller quadrilateral has points (negative 1, 0), (negative 2, 1), (0, 1), and (1, 0).
Step-by-step explanation:
<u>Larger quadrilateral</u>
Length of the top and bottom segments are 6 units.
Length of the left and right sides:
d = √[(-5 - (-2))² + (3 - 0)²] = √[3² + 3²] = √(2*3²) = 3√2 units
From point (-5, 3) to point (-2, 0) the slope is:
m = (3 - 0)/(-5 - (-2)) = -1
<u>Smaller quadrilateral</u>
Length of the top and bottom segments are 2 units.
Length of the left and right sides:
d = √[(-2 - (-1))² + (1 - 0)²] = √[1² + 1²] = √2 units
From point (-2, 1) to point (-1, 0) the slope is:
m = (1 - 0)/(-2 - (-1)) = -1
If you dilate the smaller quadrilateral by a factor of 3, you get the larger quadrilateral (they have the same slope, and 3 times length of the smaller quadrilateral is equal to the length of the larger quadrilateral).
If
then we have
By Fermat's little theorem, if
is not divisible by a prime 
, then
This works for
; in this case, we would have
then we have
By Fermat's little theorem, if
This works for