If BD= 14 and CD= 4, then BC= ?

A factory received a shipment of 38 sprockets, and the vendor who sold the items knows there are 5 sprockets in the shipment tha

weeeeeb [17]

Answer:

a) 0.00019923%

b) 47.28%

Step-by-step explanation:

a) To find the probability of all sockets in the sample being defective, we can do the following:

The first socket will be in a group where 5 of the 38 sockets are defective, so the probability is 5/38

The second socket will be in a group where 4 of the 37 sockets are defective, as the first one picked is already defective, so the probability is 4/37

Expanding this, we have that the probability of having all 5 sockets defective is: (5/38)*(4/37)*(3/36)*(2/35)*(1/34) = 0.0000019923 = 0.00019923%

b) Following the same logic of (a), the first socket have a chance of 33/38 of not being defective, as we will pick it from a group where 33 of the 38 sockets are not defective. The second socket will have a chance of 32/37, and so on.

The probability will be (33/38)*(32/37)*(31/36)*(30/35)*(29/34) = 0.4728 = 47.28%

5 0

2 years ago

Find the perimeter of the polygon defined by the coordinates (5, 12), (12, 0), (0, 0), and (-4, 12). (Round to nearest tenth) A)

zavuch27 [327]

It would be b...........

8 0

2 years ago

Read 2 more answers

Which is the smallest 0.37 0.194 0.6 0.473 0.29

wolverine [178]

0.37

0.194

0.6

0.473

0.29

the smallest digit at tenth place is 1 in 0.194, so 0.194 is the smallest here

4 0

2 years ago

Read 2 more answers

A charity fair raised $6,000 by selling 500 lottery tickets. There were two types of lottery tickets: A tickets cost $10 each, a

julsineya [31]

x= A ticket
y=b ticket
x+y=500
10x+60y=6000
-------------------
10x+60y=6000
- x+y=500 (*10) ---> 10x+10y=5000
-------------------
10x+60y=6000
- 10x+10y=5000
-------------------
50y=1000
y=1000/50
y=20
b ticket =20

x+y=500
x+20=500
x=500-20
x=480
a ticket=480
answer is the last option ,

6 0

2 years ago

A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than t

belka [17]

system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y is $x+8y=68$ and $3x+4y=64$ .

<u>Step-by-step explanation:</u>

Here we have , A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. We need to find Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y . Let's find out:

Let the price in dollars of each large candle, x, and each small candle, y .So

A customer at a store paid $64 for 3 large candles and 4 small candles

Equation is :

⇒ $3x+4y=64$ .....(1)

At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles.

Equation is :

⇒ $x+8y=68$ .......(2)

3(2)-(1) i.e.

⇒ $3(x+8y)-(3x+4y)=68(3)-64$

⇒ $20y=140$

⇒ $y=7$

So , $x+8y=68$

⇒ $x+8(7)=68$

⇒ $x=12$

Therefore , system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y is $x+8y=68$ and $3x+4y=64$ .

7 0

2 years ago